ValueError:以10为基数的int()的无效文字。

when the the last index on string has "x" or "X" (It is represent as 10) so if I have something like "1x", which mean 11 (1 + 10)

当字符串的最后一个索引有“x”或“x”(表示为10)时，如果我有“1x”，也就是11 (1 + 10)

def main():
    s1 = "013162959x"
    partial_sums(s1)


def partial_sums(s1):
    lst =[]
    sum = 0    
    for i in range(len(s1)):
       if (i == len(s1) -1) and (s1[i] == "x" or "X"):
            sum = sum + int(s1[i]) + 10
        else:
            sum = sum + int(s1[i])
        lst.append(sum)
    print(lst)


main()

I got an ValueError: invalid literal for int() with base 10: 'x'

我得到了一个ValueError:以10为基数的int()的无效文字。

the output should be [0, 1, 4, 5, 11, 13, 22, 27, 36, 46]

输出应该是[0,1,4,5,11,13,22,27,36,46]

When the string contain No "X" value it work fine.

当字符串不包含“X”值时，它可以正常工作。

def main():
    s1 = "0131629592"  
    partial_sums(s1)

def partial_sums(s1):
    lst1 =[]
    sum = 0
    for i in range(len(s1)):
        sum = sum + int(s1[i])
        lst1.append(sum)
    print(lst1)

main()

How can I fix it?

我怎样才能修好它?

1 个解决方案

#1

This statement:

这句话:

   if (i == len(s1) -1) and (s1[i] == "x" or "X"):
        sum = sum + int(s1[i]) + 10

still calls int on s1[i] even though s1[i] is "x". You simply want sum += 10.

仍然在s1[i]上调用int，尽管s1[i]是“x”。你只要求和+= 10。

However, note that or doesn't work the way you're using it. To quote the docs, "The expression x or y first evaluates x; if x is true, its value is returned; otherwise, y is evaluated and the resulting value is returned." IOW, "a" == "b" or "c" returns "c", not False, and "c" evaluates as True.

但是，请注意，或者不按照您使用它的方式工作。要引用文档，“表达式x或y首先计算x;如果x为真，则返回其值;否则，将计算y并返回结果值。IOW， "a" = "b"或"c"返回"c"，而不是False， "c"的计算结果为True。

Also, since sum is a really useful builtin, it's probably a bad idea to shadow it with a variable of your own with the same name. total is often used instead.

另外，由于sum是一个非常有用的内置函数，所以将它与同名的变量进行阴影可能是一个坏主意。total经常被使用。

#1