I looked at the other questions similar to this one, but can't figure this out still.
我查看了与此类似的其他问题,但仍无法解决这个问题。
I have a basic php file that does this:
我有一个基本的PHP文件,它执行此操作:
?php
$item='example';
$tmp = exec("python testscriptphp.py .$item");
echo $tmp;
?
While succesfully calls python that I have running on my webhostserver. Now in my python script i want something like this:
虽然成功调用了我在webhostserver上运行的python。现在在我的python脚本中我想要这样的东西:
item=$item
print item
Basically I'm asking how to pass variables from PHP to a python script and then back to php if necessary.
基本上我问的是如何将变量从PHP传递到python脚本,然后在必要时返回php。
Thanks!
1 个解决方案
#1
24
Although netcoder pretty much gave you the answer in his comment, here's an example:
尽管netcoder在他的评论中给出了答案,但这里有一个例子:
Python->PHP
example.py
import os
os.system("/usr/bin/php example2.php whatastorymark")
example2.php
<?php
echo $argv[1];
?>
PHP->Python
<?php
$item='example';
$tmp = exec("python testscriptphp.py .$item");
echo $tmp;
?>
testscriptphp.py
import sys
print sys.argv[1]
Here's how PHP's command line argument passing works: http://php.net/manual/en/reserved.variables.argv.php The same for Python: http://docs.python.org/library/sys.html#sys.argv
以下是PHP的命令行参数传递的工作方式:http://php.net/manual/en/reserved.variables.argv.php Python的相同内容:http://docs.python.org/library/sys.html#sys .argv
#1
24
Although netcoder pretty much gave you the answer in his comment, here's an example:
尽管netcoder在他的评论中给出了答案,但这里有一个例子:
Python->PHP
example.py
import os
os.system("/usr/bin/php example2.php whatastorymark")
example2.php
<?php
echo $argv[1];
?>
PHP->Python
<?php
$item='example';
$tmp = exec("python testscriptphp.py .$item");
echo $tmp;
?>
testscriptphp.py
import sys
print sys.argv[1]
Here's how PHP's command line argument passing works: http://php.net/manual/en/reserved.variables.argv.php The same for Python: http://docs.python.org/library/sys.html#sys.argv
以下是PHP的命令行参数传递的工作方式:http://php.net/manual/en/reserved.variables.argv.php Python的相同内容:http://docs.python.org/library/sys.html#sys .argv