Android逆向破解表单注册程序

时间:2023-03-08 20:52:44
Android逆向破解表单注册程序

Android逆向破解表单注册程序

Android开发

ADT: android studio(as)

程序界面如下,注册码为6位随机数字,注册成功时弹出通知注册成功,注册失败时弹出通知注册失败

Android逆向破解表单注册程序

布局代码

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical">
<TextView
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:gravity="center"
android:text="用户注册"
android:textSize="28sp" />
<EditText
android:id="@+id/Username"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:text="6位用户名"/>
<EditText
android:id="@+id/Register"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:text="6位注册码"/>
<Button
android:id="@+id/BTN_Login"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:text="注册" />
</LinearLayout>

主程序代码

package com.example.mark.myfirstregister;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;
public class MainActivity extends AppCompatActivity {
EditText edit_Name;
EditText Reg;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
edit_Name = (EditText) findViewById(R.id.Username);
Reg = (EditText) findViewById(R.id.Register);
Button btn_reg = (Button) findViewById(R.id.BTN_Login);
btn_reg.setOnClickListener(new View.OnClickListener() { @Override
public void onClick(View v) {
checkReg(edit_Name.getText().toString().trim(),Reg.getText().toString().trim());
}
});
}
public void checkReg(String name, String reg){
int numcode = (int) ((Math.random() * 9 + 1) * 100000);
int n = 6;
if(name.length() == 6 && reg.equals(numcode)){
Toast.makeText(MainActivity.this,"注册成功",Toast.LENGTH_SHORT).show();
}
else
Toast.makeText(MainActivity.this,"注册失败",Toast.LENGTH_SHORT).show();
}
}

Android逆向破解

tool: apktool

# 反编译
apktool d[ecode] [options] <file_apk>
# 编译
apktool b[uild] [options] <app_path>

反编译apk,执行 apktool d target.apk -o /path,之后生成一些目录,res存放资源文件,smali存放被反编译的smali代码。关键代码存放在smali目录下的MainActivity.smali文件,打开后进行分析。

.class public Lcom/example/mark/myfirstregister/MainActivity;
.super Landroid/support/v7/app/AppCompatActivity;
.source "MainActivity.java" # instance fields
.field Reg:Landroid/widget/EditText; .field edit_Name:Landroid/widget/EditText; # direct methods
.method public constructor <init>()V
.locals 0 .line 14
invoke-direct {p0}, Landroid/support/v7/app/AppCompatActivity;-><init>()V return-void
.end method # virtual methods
.method public checkReg(Ljava/lang/String;Ljava/lang/String;)V
.locals 5
.param p1, "name" # Ljava/lang/String;
.param p2, "reg" # Ljava/lang/String; .line 35
invoke-static {}, Ljava/lang/Math;->random()D move-result-wide v0 const-wide/high16 v2, 0x4022000000000000L # 9.0 mul-double v0, v0, v2 const-wide/high16 v2, 0x3ff0000000000000L # 1.0 add-double/2addr v0, v2 const-wide v2, 0x40f86a0000000000L # 100000.0 mul-double v0, v0, v2 double-to-int v0, v0 .line 36
.local v0, "numcode":I
const/4 v1, 0x6 .line 37
.local v1, "n":I
invoke-virtual {p1}, Ljava/lang/String;->length()I move-result v2 const/4 v3, 0x0 const/4 v4, 0x6 if-ne v2, v4, :cond_0 invoke-static {v0}, Ljava/lang/Integer;->valueOf(I)Ljava/lang/Integer; move-result-object v2 invoke-virtual {p2, v2}, Ljava/lang/String;->equals(Ljava/lang/Object;)Z move-result v2 if-eqz v2, :cond_0 .line 38
const-string v2, "\u6ce8\u518c\u6210\u529f" invoke-static {p0, v2, v3}, Landroid/widget/Toast;->makeText(Landroid/content/Context;Ljava/lang/CharSequence;I)Landroid/widget/Toast; move-result-object v2 invoke-virtual {v2}, Landroid/widget/Toast;->show()V goto :goto_0 .line 41
:cond_0
const-string v2, "\u6ce8\u518c\u5931\u8d25" invoke-static {p0, v2, v3}, Landroid/widget/Toast;->makeText(Landroid/content/Context;Ljava/lang/CharSequence;I)Landroid/widget/Toast; move-result-object v2 invoke-virtual {v2}, Landroid/widget/Toast;->show()V .line 43
:goto_0
return-void
.end method .method protected onCreate(Landroid/os/Bundle;)V
.locals 2
.param p1, "savedInstanceState" # Landroid/os/Bundle; .line 20
invoke-super {p0, p1}, Landroid/support/v7/app/AppCompatActivity;->onCreate(Landroid/os/Bundle;)V .line 21
const v0, 0x7f09001c invoke-virtual {p0, v0}, Lcom/example/mark/myfirstregister/MainActivity;->setContentView(I)V .line 22
const v0, 0x7f070008 invoke-virtual {p0, v0}, Lcom/example/mark/myfirstregister/MainActivity;->findViewById(I)Landroid/view/View; move-result-object v0 check-cast v0, Landroid/widget/EditText; iput-object v0, p0, Lcom/example/mark/myfirstregister/MainActivity;->edit_Name:Landroid/widget/EditText; .line 23
const v0, 0x7f070005 invoke-virtual {p0, v0}, Lcom/example/mark/myfirstregister/MainActivity;->findViewById(I)Landroid/view/View; move-result-object v0 check-cast v0, Landroid/widget/EditText; iput-object v0, p0, Lcom/example/mark/myfirstregister/MainActivity;->Reg:Landroid/widget/EditText; .line 24
const v0, 0x7f070001 invoke-virtual {p0, v0}, Lcom/example/mark/myfirstregister/MainActivity;->findViewById(I)Landroid/view/View; move-result-object v0 check-cast v0, Landroid/widget/Button; .line 25
.local v0, "btn_reg":Landroid/widget/Button;
new-instance v1, Lcom/example/mark/myfirstregister/MainActivity$1; invoke-direct {v1, p0}, Lcom/example/mark/myfirstregister/MainActivity$1;-><init>(Lcom/example/mark/myfirstregister/MainActivity;)V invoke-virtual {v0, v1}, Landroid/widget/Button;->setOnClickListener(Landroid/view/View$OnClickListener;)V .line 33
return-void
.end method

关键部分代码在checkReg()方法中,注册成功的smali代码如下

if-eqz v2, :cond_0

.line 38
const-string v2, "\u6ce8\u518c\u6210\u529f"

对照AS38行的代码

Toast.makeText(MainActivity.this,"注册成功",Toast.LENGTH_SHORT).show();

由此可以确定程序破解的关键,直接修改if-eqzif-nez,然后重新编译。

apktool b /path/ -o /path/1.apk

安装后打开,输入任意6位用户名和注册码即可成功注册。

Android逆向破解表单注册程序