在python中将字符串转换为元组

I have a string returnd from a software like "('mono')" from that I needed to convert string to tuple .

我有一个像“('mono')这样的软件的字符串返回”,我需要将字符串转换为元组。

that I was thinking using ast.literal_eval("('mono')") but it is saying malformed string.

我正在考虑使用ast.literal_eval(“('mono')”),但它说的是格式错误的字符串。

5 个解决方案

#1

Since you want tuples, you must expect lists of more than element in some cases. Unfortunately you don't give examples beyond the trivial (mono), so we have to guess. Here's my guess:

既然你想要元组,那么在某些情况下你必须要有超过元素的列表。不幸的是,除了琐碎的(单声道)之外你不会给出例子,所以我们不得不猜测。这是我的猜测:

"(mono)"
"(two,elements)"
"(even,more,elements)"

If all your data looks like this, turn it into a list by splitting the string (minus the surrounding parens), then call the tuple constructor. Works even in the single-element case:

如果您的所有数据都是这样,请通过拆分字符串(减去周围的parens)将其转换为列表,然后调用元组构造函数。甚至在单元素情况下也可以工作:

assert data[0] == "(" and data[-1] == ")"
elements = data[1:-1].split(",")
mytuple = tuple(elements)

Or in one step: elements = tuple(data[1:-1].split(",")). If your data doesn't look like my examples, edit your question to provide more details.

或者一步:elements = tuple(data [1:-1] .split(“,”))。如果您的数据与我的示例不同,请修改您的问题以提供更多详细信息。

#2

How about using regular expressions ?

如何使用正则表达式?

In [1686]: x
Out[1686]: '(mono)'

In [1687]: tuple(re.findall(r'[\w]+', x))
Out[1687]: ('mono',)

In [1688]: x = '(mono), (tono), (us)'

In [1689]: tuple(re.findall(r'[\w]+', x))
Out[1689]: ('mono', 'tono', 'us')

In [1690]: x = '(mono, tonous)'

In [1691]: tuple(re.findall(r'[\w]+', x))
Out[1691]: ('mono', 'tonous')

#3

Try to this

试试这个

a = ('mono')
print tuple(a)      # <-- you create a tuple from a sequence 
                    #(which is a string)
print tuple([a])    # <-- you create a tuple from a sequence 
                    #(which is a list containing a string)
print tuple(list(a))# <-- you create a tuple from a sequence 
                    #     (which you create from a string)
print (a,)# <-- you create a tuple containing the string
print (a)

Output :

('m', 'o', 'n', 'o')
('mono',)
('m', 'o', 'n', 'o')
('mono',)
mono

#4

I assume that the desired output is a tuple with a single string: ('mono',)

我假设所需的输出是一个带有单个字符串的元组:('mono',)

A tuple of one has a trailing comma in the form (tup,)

一个元组的元组在表单中有一个尾随逗号(tup,)

a = '(mono)'
a = a[1:-1] # 'mono': note that the parenthesis are removed removed 
            # if they are inside the quotes they are treated as part of the string!
b = tuple([a]) 
b
> ('mono',)
# the final line converts the string to a list of length one, and then the list to a tuple

#5

Convert string to tuple? Just apply tuple:

将字符串转换为元组?只需应用元组:

>>> tuple('(mono)')
('(', 'm', 'o', 'n', 'o', ')')

Now it's a tuple.

现在它是一个元组。

#1