贴个模板:平常的跟高精度java的;
int:
#pragma comment(linker, "/STACK:1024000000,1024000000")
#include<iostream>
#include<cstdio>
#include<cmath>
#include<string>
#include<queue>
#include<algorithm>
#include<stack>
#include<cstring>
#include<vector>
#include<list>
#include<set>
#include<map>
using namespace std;
#define LL long long
#define pi (4*atan(1.0))
#define eps 1e-14
#define bug(x) cout<<"bug"<<x<<endl;
const int N=1e6+10,M=1e6+10,inf=1e9+10;
const LL mod=1e9+7; int main()
{
double k=(sqrt(5.0)+1)/2;
int n;
scanf("%d",&n);
while(n--)
{
int a,b;
scanf("%d%d",&a,&b);
if(a>b)swap(a,b);
int x=(b-a)*k;
if(x==a)printf("B\n");
else printf("A\n");
}
return 0;
}
java:
import java.util.*;
import java.math.*; public class Main {
public static void main(String[] args) {
Scanner cin = new Scanner(System.in);
BigInteger k=new BigInteger("16180339887498948482045868343656381177203091798057628621354486227052604628189024497072072041893911374");
BigInteger p=new BigInteger("10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000");
int T;
T=cin.nextInt();
while(T--!=0)
{
BigInteger nn=cin.nextBigInteger();
BigInteger mm=cin.nextBigInteger();
BigInteger n=nn.min(mm);
BigInteger m=nn.max(mm);
BigInteger j=m.subtract(n);
j=j.multiply(k);
j=j.divide(p);
if(j.equals(n))
System.out.println("B");
else
System.out.println("A");
}
}
}