I have a regular expression to validate the dates and it works fine, this is it
我有一个正则表达式来验证日期,它工作正常,就是这样
^(0[1-9]|[1-9]|1[012])[- /.](0[1-9]|[1-9]|[12][0-9]|3[01])[- /.](19|20)\d\d$
But I want to validate it using the javascript. I tried with this
但我想用javascript验证它。我试过这个
var ck_effectivedate= /^(0[1-9]|[1-9]|1[012])[- /.](0[1-9]|[1-9]|[12][0-9]|3[01])[- /.](19|20)\d\d$/;
function radtxtbxNewEffectiveDateOnBlur(sender, eventArgs) {
if (!ck_effectivedate.test(sender.get_value())) {
alert('matches');
}
else
{
alert('does not match');
}
}
But, the regular expression is not working, because of the presence of /
character in my regular expression which is also used to encapsulate the regular expression in java script.
但是,正则表达式不起作用,因为我的正则表达式中存在/字符,它也用于在java脚本中封装正则表达式。
If I remove the /
character then it works, but I want to use that in my string. Please help.
如果我删除/字符然后它工作,但我想在我的字符串中使用它。请帮忙。
1 个解决方案
#1
3
You simply need to escape the special characters with a backslash \
:
您只需要使用反斜杠\来转义特殊字符:
^(0[1-9]|[1-9]|1[012])[- \/.](0[1-9]|[1-9]|[12][0-9]|3[01])[- \/.](19|20)\d\d$
References:
参考文献:
- JavaScript Regular Expressions.
- JavaScript正则表达式。
#1
3
You simply need to escape the special characters with a backslash \
:
您只需要使用反斜杠\来转义特殊字符:
^(0[1-9]|[1-9]|1[012])[- \/.](0[1-9]|[1-9]|[12][0-9]|3[01])[- \/.](19|20)\d\d$
References:
参考文献:
- JavaScript Regular Expressions.
- JavaScript正则表达式。