I have a text file that contains these 9 lines:
我有一个包含这9行的文本文件：
Successfully started load asymmetric-song-851:bqjob_r08ac53fc_0000014bfdd9d371_1
Successfully started load asymmetric-song-851:bqjob_r44afbc8a_0000014bfdd9e792_1
Successfully started load asymmetric-song-851:bqjob_r7874a1e7_0000014bfdd9f7ca_1
Successfully started load asymmetric-song-851:bqjob_r11fb8a32_0000014bfdda0583_1
Successfully started load asymmetric-song-851:bqjob_r6b174b76_0000014bfdda1486_1
Successfully started load asymmetric-song-851:bqjob_r65772621_0000014bfdda239f_1
Successfully started load asymmetric-song-851:bqjob_r6e1918e0_0000014bfdda312d_1
Successfully started load asymmetric-song-851:bqjob_r08e15175_0000014bfdda3fa7_1
Successfully started load asymmetric-song-851:bqjob_r319141ff_0000014bfdda4e9e_1
I want to capture only jobid from each line,i.e. bqjob_r08ac53fc_0000014bfdd9d371_1. So the output text file should be like this:
我想从每一行只捕获jobid，即。 bqjob_r08ac53fc_0000014bfdd9d371_1。所以输出文本文件应该是这样的：
bqjob_r0f2cb934_0000014bfe9c563c_1
bqjob_r6022172e_0000014bfe9c6318_1
bqjob_r67eae0a9_0000014bfe9c6f12_1
bqjob_r56ab0212_0000014bfe9c7d67_1
bqjob_r75d2e18d_0000014bfe9c89aa_1
bqjob_r1c73e74f_0000014bfe9c9576_1
bqjob_r31dae331_0000014bfe9ca28e_1
bqjob_r56873b54_0000014bfe9caeb7_1
bqjob_r0edb7092_0000014bfe9cbb8c_1
1 个解决方案
#1
1
Split the string on : and echo the second part into a new file.
拆分字符串：并将第二部分回显到新文件中。
for /F "tokens=1,2 delims=:" %%A in (data.txt) do echo %%B>>output.txt
This code assumes that your text file is called data.txt and that the lines you've shown us are the only lines in the file.
此代码假定您的文本文件名为data.txt，并且您向我们显示的行是文件中的唯一行。
#1
1
Split the string on : and echo the second part into a new file.
拆分字符串：并将第二部分回显到新文件中。
for /F "tokens=1,2 delims=:" %%A in (data.txt) do echo %%B>>output.txt
This code assumes that your text file is called data.txt and that the lines you've shown us are the only lines in the file.
此代码假定您的文本文件名为data.txt，并且您向我们显示的行是文件中的唯一行。