Hi first time posting for SQL,
您好第一次发布SQL,
I need to compare two different columns from two different tables in SQL.
我需要比较SQL中两个不同表的两个不同列。
For example there is two tables and each have one column in them and I need to compare them.
例如,有两个表,每个表中都有一列,我需要比较它们。
Column1 is in table1 and column2 is in table2.
Column1在table1中,column2在table2中。
I need to compare column1 and column2 for differences, I have looked online but was unable to find a query that would be able to help.
我需要比较column1和column2的差异,我已经在线查看但无法找到能够提供帮助的查询。
Essentially I need to find the inconsistencies in the two columns from two different tables.
基本上我需要从两个不同的表中找到两列中的不一致。
3 个解决方案
#1
0
The following Oracle SQL would be a solution provided you have an id
that you can join on between the two tables.
如果您具有可以在两个表之间连接的ID,则以下Oracle SQL将是一种解决方案。
select tab1.id,
case
when tab1.col1 > tab2.col1 OR tab1.col1 < tab2.col1 then 'Different'
else 'Equals'
end
from tab1, tab2
where tab1.id = tab2.id;
Test data SQL:
测试数据SQL:
create table tab1 ( id number, col1 varchar2(20));
create table tab2 ( id number, col1 varchar2(20));
insert into tab1 values (1, 'ABCD');
insert into tab1 values (2, 'EFGH');
insert into tab1 values (3, 'WXYZ');
insert into tab2 values (1, 'ABCD');
insert into tab2 values (2, 'EFG');
insert into tab2 values (3, 'ZYXW');
commit;
Results:
结果:
ID CASEWHENT
1 Equals
2 Different
3 Different
#2
0
Try this:
尝试这个:
WITH x AS (SELECT 1 AS ID, 'THE QUICK BROWN' AS tab1 FROM dual UNION ALL
SELECT 2 AS ID, 'FOX JUMPS OVER' AS tab1 FROM dual),
y AS (SELECT 1 AS ID, 'THE QUICK BROWN FOX' AS tab2 FROM DUAL UNION ALL
SELECT 2 AS ID, 'FOX JUMPS OVER' AS TAB2 FROM DUAL)
SELECT X.ID,X.tab1,Y.tab2,(CASE WHEN (X.tab1 = tab2)
THEN 'Tab1 is equal Tab2'
ELSE 'Tab1 is not equal to Tab2' END) AS Remarks
FROM X INNER JOIN Y ON X.ID = Y.ID;
OUTPUT:
OUTPUT:
ID TAB1 TAB2 REMARKS
1 THE QUICK BROWN THE QUICK BROWN FOX Tab1 is not equal to Tab2
2 FOX JUMPS OVER FOX JUMPS OVER Tab1 is equal Tab2
#3
0
You can do inner join and then find the difference.
你可以做内连接,然后找到差异。
SELECT
table1.column1,
table2.column2,
(CASE WHEN (table1.column1 = table2.column2 THEN 'No change' ELSE 'Change DETECTED' END)) AS Difference
FROM
table1 INNER JOIN table2 ON table1.id=table2.id
#1
0
The following Oracle SQL would be a solution provided you have an id
that you can join on between the two tables.
如果您具有可以在两个表之间连接的ID,则以下Oracle SQL将是一种解决方案。
select tab1.id,
case
when tab1.col1 > tab2.col1 OR tab1.col1 < tab2.col1 then 'Different'
else 'Equals'
end
from tab1, tab2
where tab1.id = tab2.id;
Test data SQL:
测试数据SQL:
create table tab1 ( id number, col1 varchar2(20));
create table tab2 ( id number, col1 varchar2(20));
insert into tab1 values (1, 'ABCD');
insert into tab1 values (2, 'EFGH');
insert into tab1 values (3, 'WXYZ');
insert into tab2 values (1, 'ABCD');
insert into tab2 values (2, 'EFG');
insert into tab2 values (3, 'ZYXW');
commit;
Results:
结果:
ID CASEWHENT
1 Equals
2 Different
3 Different
#2
0
Try this:
尝试这个:
WITH x AS (SELECT 1 AS ID, 'THE QUICK BROWN' AS tab1 FROM dual UNION ALL
SELECT 2 AS ID, 'FOX JUMPS OVER' AS tab1 FROM dual),
y AS (SELECT 1 AS ID, 'THE QUICK BROWN FOX' AS tab2 FROM DUAL UNION ALL
SELECT 2 AS ID, 'FOX JUMPS OVER' AS TAB2 FROM DUAL)
SELECT X.ID,X.tab1,Y.tab2,(CASE WHEN (X.tab1 = tab2)
THEN 'Tab1 is equal Tab2'
ELSE 'Tab1 is not equal to Tab2' END) AS Remarks
FROM X INNER JOIN Y ON X.ID = Y.ID;
OUTPUT:
OUTPUT:
ID TAB1 TAB2 REMARKS
1 THE QUICK BROWN THE QUICK BROWN FOX Tab1 is not equal to Tab2
2 FOX JUMPS OVER FOX JUMPS OVER Tab1 is equal Tab2
#3
0
You can do inner join and then find the difference.
你可以做内连接,然后找到差异。
SELECT
table1.column1,
table2.column2,
(CASE WHEN (table1.column1 = table2.column2 THEN 'No change' ELSE 'Change DETECTED' END)) AS Difference
FROM
table1 INNER JOIN table2 ON table1.id=table2.id