I have a simple dataframe in pandas that has two numeric columns. I want to make a histogram out of the columns using matplotlib through pandas. The example below does not work:
我在熊猫中有一个简单的dataframe,它有两个数字列。我想用matplotlib在熊猫里做一个直方图。下面的例子不起作用:
In [6]: pandas.__version__
Out[6]: '0.14.1'
In [7]: df
Out[7]:
a b
0 1 20
1 2 40
2 3 30
3 4 30
4 4 3
5 3 5
In [8]: df.plot(kind="hist")
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
<ipython-input-8-4f53176a4683> in <module>()
----> 1 df.plot(kind="hist")
/software/lib/python2.7/site-packages/pandas/tools/plotting.pyc in plot_frame(frame, x, y, subplots, sharex, sharey, use_index, figsize, grid, legend, rot, ax, style, title, xlim, ylim, logx, logy, xticks, yticks, kind, sort_columns, fontsize, secondary_y, **kwds)
2095 klass = _plot_klass[kind]
2096 else:
-> 2097 raise ValueError('Invalid chart type given %s' % kind)
2098
2099 if kind in _dataframe_kinds:
ValueError: Invalid chart type given hist
why does it say invalid chart type? the columns are numeric and can be made into histograms.
为什么说无效的图表类型?这些列是数字的,可以做成直方图。
2 个解决方案
#1
14
DataFrame
has its own hist
method:
DataFrame有自己的hist方法:
df =pd.DataFrame({'col1':np.random.randn(100),'col2':np.random.randn(100)})
df.hist(layout=(1,2))
draws a histogram for each valid column of the dataframe
.
为dataframe的每个有效列绘制直方图。
#2
2
I don't believe 'hist' was a supported type in 0.14.1. Try df.hist() instead
我不认为hist是0.14.1中支持的类型。尝试df.hist()
#1
14
DataFrame
has its own hist
method:
DataFrame有自己的hist方法:
df =pd.DataFrame({'col1':np.random.randn(100),'col2':np.random.randn(100)})
df.hist(layout=(1,2))
draws a histogram for each valid column of the dataframe
.
为dataframe的每个有效列绘制直方图。
#2
2
I don't believe 'hist' was a supported type in 0.14.1. Try df.hist() instead
我不认为hist是0.14.1中支持的类型。尝试df.hist()