[LeetCode] 102. Binary Tree Level Order Traversal 二叉树层序遍历

Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level).

For example:
Given binary tree {3,9,20,#,#,15,7},

return its level order traversal as:

[

  [3],

  [9,20],

  [15,7]

]

层序遍历二叉树是典型的广度优先搜索 BFS 的应用，但是这里稍微复杂一点的是，要把各个层的数分开，存到一个二维向量里面，大体思路还是基本相同的，建立一个 queue，然后先把根节点放进去，这时候找根节点的左右两个子节点，这时候去掉根节点，此时 queue 里的元素就是下一层的所有节点，用一个 for 循环遍历它们，然后存到一个一维向量里，遍历完之后再把这个一维向量存到二维向量里，以此类推，可以完成层序遍历，参见代码如下：

解法一：

class Solution {

public:

    vector<vector<int>> levelOrder(TreeNode* root) {

        if (!root) return {};

        vector<vector<int>> res;

        queue<TreeNode*> q{{root}};

        while (!q.empty()) {

            vector<int> oneLevel;

            for (int i = q.size(); i > ; --i) {

                TreeNode *t = q.front(); q.pop();

                oneLevel.push_back(t->val);

                if (t->left) q.push(t->left);

                if (t->right) q.push(t->right);

            }

            res.push_back(oneLevel);

        }

        return res;

    }

};

下面来看递归的写法，核心就在于需要一个二维数组，和一个变量 level，关于 level 的作用可以参见博主的另一篇博客 Binary Tree Level Order Traversal II 中的讲解，参见代码如下：

解法二：

class Solution {

public:

    vector<vector<int>> levelOrder(TreeNode* root) {

        vector<vector<int>> res;

        levelorder(root, , res);

        return res;

    }

    void levelorder(TreeNode* node, int level, vector<vector<int>>& res) {

        if (!node) return;

        if (res.size() == level) res.push_back({});

        res[level].push_back(node->val);

        if (node->left) levelorder(node->left, level + , res);

        if (node->right) levelorder(node->right, level + , res);

    }

};

Github 同步地址：

https://github.com/grandyang/leetcode/issues/102

类似题目：

Binary Tree Level Order Traversal II

Binary Tree Zigzag Level Order Traversal

Minimum Depth of Binary Tree

Binary Tree Vertical Order Traversal

Average of Levels in Binary Tree

N-ary Tree Level Order Traversal

参考资料：

https://leetcode.com/problems/binary-tree-level-order-traversal/

https://leetcode.com/problems/binary-tree-level-order-traversal/discuss/33445/Java-Solution-using-DFS