将字符串转换为特定的数组格式

What I need to do is convert something like this:

我需要做的是转换如下内容:

"id,name,user[id,email]"

into this array:

这个数组:

["id", "name", {"user"=>["id", "email"]}]

What is the best way to do that? I think some function like split or scan can help, but I don't have much knowledge in regex to solve this.

最好的方法是什么?我认为像split或scan这样的函数可以有所帮助，但是我在regex中没有太多的知识来解决这个问题。

2 个解决方案

#1

Just out of curiosity:

只是出于好奇:

▶ str = "id,name,user[id,email]"
▶ eval "[#{str.gsub(/(\w+)\[(.*?)\]/, '{\1=>[\2]}').gsub(/\w+/, ':\0')}]"
#⇒ [
#  [0] :id,
#  [1] :name,
#  [2] {
#    :user => [
#      [0] :id,
#      [1] :email
#    ]
#  }
#]

Disclamer: to use eval in production one must understand risks.

Disclamer:在生产中使用eval必须了解风险。

UPD Safe evaling (note that every ASCII \w symbol is converted to it’s wide pair from UTF-8 to prevent injection; not the best way around, but it works nicely unless you have ruby functions named with wide characters):

UPD安全报警(注意，每个ASCII \w符号从UTF-8转换为宽对，以防止注入;这并不是最好的方法，但是它可以很好地工作，除非你有用宽字符命名的ruby函数):

▶ safe = str.gsub(/\w/) do |e| 
▷   e.each_codepoint.map do |cp| 
▷     cp + 0xFF00 - 0x0020
▷   end.pack('U')
▷ end
#⇒ "ｉｄ,ｎａｍｅ,ｕｓｅｒ[ｉｄ,ｅｍａｉｌ]"
▶ eval "[#{safe.gsub(/(\p{L}+)\[(.*?)\]/, '{\1=>[\2]}').gsub(/\p{L}+/, ':\0')}]"
#⇒ [
#  [0] :ｉｄ,
#  [1] :ｎａｍｅ,
#  [2] {
#    :ｕｓｅｒ => [
#      [0] :ｉｄ,
#      [1] :ｅｍａｉｌ
#    ]
#  }
#]

Now you are free to turn keys back from wide characters to ASCII.

现在您可以*地将键从宽字符转回ASCII。

#2

string = "id,name,user[id,email]"
parts = string.split(/[\,,\[,\]]/)
[parts[0], parts[1], {parts[2] => [parts[3], parts[4]]}]

You may also want to have some validation or not use all the parts if the first id is supposed to be the same as the second.

如果第一个id应该与第二个id相同，您可能还想进行一些验证，或者不使用所有的部分。

#1