Python：如何删除列表列表中的重复列表？

I want to remove all duplicates list from a list of list.

我想从列表列表中删除所有重复列表。

So I have a list of lists like this.

所以我有一个像这样的列表。

a = [[1,2],[1,2],[3,4,5],[3,4,5],[3,4,5]]

I want to have:

我希望有:

b = [[1,2],[3,4,5]]

I don't know how to do.

我不知道该怎么做。

Thank you

2 个解决方案

#1

You could use a set:

你可以使用一套:

b_set = set(map(tuple,a))  #need to convert the inner lists to tuples so they are hashable
b = map(list,b_set) #Now convert tuples back into lists (maybe unnecessary?)

Or, if you prefer list comprehensions/generators:

或者,如果您更喜欢列表推导/生成器:

b_set = set(tuple(x) for x in a)
b = [ list(x) for x in b_set ]

Finally, if order is important, you can always sort b:

最后,如果订单很重要,您可以随时排序b:

b.sort(key = lambda x: a.index(x) )

#2

See mgilson's answer if the order of the lists is not important. If you want to retain the order, do something like:

如果列表的顺序不重要,请参阅mgilson的答案。如果您想保留订单,请执行以下操作:

b = list()
for sublist in a:
    if sublist not in b:
        b.append(sublist)

This will keep the order in the original list. However, it is slower and more verbose than using sets.

这将使订单保持在原始列表中。但是,它比使用集更慢,更冗长。

#1