删除字符串开头和结尾的方括号

I would like to remove square brackets from beginning and end of a string, if they are existing.

我想从字符串的开头和结尾删除方括号,如果它们存在的话。

[Just a string]
Just a string
Just a string [comment]
[Just a string [comment]]

Should result in

应该导致

Just a string
Just a string
Just a string [comment]
Just a string [comment]

I tried to build an regex, but I don't get it in a correct way, as it doesn't look for the position:

我试图构建一个正则表达式,但我没有以正确的方式得到它,因为它不寻找位置:

string.replace(/[\[\]]+/g,'')

3 个解决方案

#1

string.replace(/^\[(.+)\]$/,'$1')

should do the trick.

应该做的伎俩。

^ matches the begining of the string

^匹配字符串的开头

$ matches the end of the string.

$匹配字符串的结尾。

(.+) matches everything in between, to report it back in the final string.

(。+)匹配中间的所有内容,在最终字符串中报告。

#2

Probably a better reg exp to do it, but a basic one would be:

可能是一个更好的reg exp来做,但一个基本的将是:

var strs = [
  "[Just a string]",
  "Just a string",
  "Just a string [comment]",
  "[Just a string [comment]]"
];

var re = /^\[(.+)\]$/;
strs.forEach( function (str) {
  var updated = str.replace(re,"$1");
  console.log(updated);
});

Reg Exp Visualizer

#3

Blue112 provided a solution to remove [ and ] from the beginning/end of a line (if both are present).

Blue112提供了从行的开头/结尾删除[和]的解决方案(如果两者都存在的话)。

To remove [ and ] from start/end of a string (if both are present) you need

要从字符串的开头/结尾删除[和](如果两者都存在),则需要

input.replace(/^\[([\s\S]*)]$/,'$1')

input.replace(/^\[([^]*)]$/,'$1')

In JS, to match any symbol including a newline, you either use [\s\S] (or [\w\W] or [\d\D]), or [^] that matches any non-nothing.

在JS中,为了匹配包括换行符在内的任何符号,您可以使用[\ s \ S](或[\ w \ W]或[\ d \ D])或[^]匹配任何非空格。

var s = "[word  \n[line]]";
console.log(s.replace(/^\[([\s\S]*)]$/, "$1"));

#1

string.replace(/^\[(.+)\]$/,'$1')