I wrote a function that works as follows: matrix[24787][24788] = generate_value(source, 24787, 24788)
我写了一个函数如下:matrix [24787] [24788] = generate_value(source,24787,24788)
I want to generalize this to matrix = generate_value(source, <array of indices>, <array of columns>)
and have the entire matrix filled in. How can I do this, short of writing two loops?
我想将此概括为matrix = generate_value(source,
Edit: Here is generate_value
-
编辑:这是generate_value -
def generate_value(source, id_a, id_b):
intersection = pd.merge(source.get_group(id_a), source.get_group(id_b), how='outer', on='merge_field')
intersection.val_x.fillna(value=0, inplace=True)
intersection.val_y.fillna(value=0, inplace=True)
intersection.total_value_differences = abs(intersection.val_x - intersection.val_y)
return sum(intersection.total_value_differences)
I can rewrite it if necessary.
如有必要,我可以重写它。
1 个解决方案
#1
Looks impossible for this function in pandas at the moment.
目前在熊猫中看起来这个功能是不可能的。
#1
Looks impossible for this function in pandas at the moment.
目前在熊猫中看起来这个功能是不可能的。