Swift等价的c++指针/引用约定?

时间:2022-02-28 21:41:18

As a C++ dev picking up Swift, I'm wondering how, in a struct or other class, to store a "pointer" or "reference" to a property of of another object of another class.

作为一个c++开发人员,我想知道,在一个结构或其他类中,如何将一个“指针”或“引用”存储到另一个类的另一个对象的属性中。

For example- a controlResponder class (or struct) that listens for events to modify the value target of a target in an effect class.

例如,一个controlResponder类(或struct),它侦听事件以修改effect类中目标的值目标。

Control responder:

控制响应器:

struct controlResponder {
    var ccNum : Int!  // CC number to respond to
    var target : Double! // Points to the variable of another object
    var min : Double!
    var max : Double!
}

Effects, in my case, can be of different classes but the thing that will be targeted for modification will always be a Double (To be precise- I'm working with AudioKit and am targeting effects like AKVariableDelay.time, or AKMoogLadderFilter.cutoff )

在我的例子中,效果可以是不同的类,但是用于修改的目标总是双精度的(准确地说——我正在处理AudioKit,目标是效果,比如AKVariableDelay)。时间,或者AKMoogLadderFilter。截止)

Any insight would be greatly appreciated, thanks!

非常感谢您的理解,谢谢!

Below is an abridged version of some of my actual (non functioning) code:

以下是我的一些实际(非功能)代码的节略版本:

import Foundation
import AudioKit
import SwiftyJSON

class Effect : AKNode, AKMIDIListener {

  enum CustomError: Error {
    case badEffectName
  }

  struct ccListener {
    var ccNum : Int!
    var target : Int!
    var min : Double!
    var max : Double!
  }

  var listeners : [ccListener]

  var effectType = ""
  var effect = AKNode()
  var channel = 0
  var midi : AKMIDI

  init(connectionInput : AKNode, midi : AKMIDI, subJson : JSON, channel : Int) throws {

    self.midi = midi
    self.channel = channel
    var insertType = subJson["type"]

    if insertType == "distortion" {
      print("Adding a DISTORTION")
      effect = AKTanhDistortion(connectionInput)

      if let efx = effect as? AKTanhDistortion {
        let gainVal = random(subJson["gain random low"].doubleValue, subJson["gain random high"].doubleValue)
        print("gainVal: \(gainVal)")
        efx.pregain = gainVal
      }

    }
    else if insertType == "moog" {

      print("Adding a MOOG FILTER")
      /// CUTOFF
      let cutoffVal = random(subJson["cutoff random low"].doubleValue, subJson["cutoff random high"].doubleValue)
      print("cutoffVal: \(cutoffVal)")
      /// RESONANCE
      let resonanceVal = random(subJson["resonance random low"].doubleValue, subJson["resonance random high"].doubleValue)
      print("resonanceVal: \(resonanceVal)")

      effect = AKMoogLadder(connectionInput,
        cutoffFrequency: cutoffVal,
        resonance: resonanceVal)
    }
    else {
      print("BAD EFFECT TYPE: \(insertType)")
      throw CustomError.badEffectName
    }

    /////// MIDIZ

    midi.openInput("vIn")

    super.init()

    for (key, cc) in subJson["ccs"] as JSON {
      let efx = effect as! AKMoogLadder
      listeners.append(ccListener(ccNum: cc["cc number"].intValue, target: efx.cutoffFrequency, min: cc["min"].doubleValue, max: cc["max"].doubleValue))
    }

    midi.addListener(self)
    print("End of Effect init()")
  }


  func receivedMIDIController(_ controller: MIDIByte, value: MIDIByte, channel: MIDIChannel) {
    print("Self channel: \(self.channel), incoming channel: \(Int(channel))")
      if self.channel == Int(channel){
        print("Effect got a CC!")
      }
    }

    func changeVal(ccNum: Int, newValue: Int) {

      for listener in listeners {
        if listener.ccNum == ccNum {
          listener.target = newValue
        }
      }

    }

  }

1 个解决方案

#1


1  

In Swift, the only pointers that you can reliably store are those allocated with UnsafeMutablePointer.allocate. The pointers that you can get from the address-of operator and withUnsafeMutablePointer are cheats and they are only valid for a short time; using them beyond that point will have unpredictable results.

在Swift中,惟一可以可靠存储的指针是那些使用unsafemutablepointer. allocation分配的指针。你可以从寻址操作符和unsafemutablepointer中获得的指针是欺骗,它们只在短时间内有效;超过这一点使用它们将产生不可预测的结果。

This means that, generally speaking, you can't store a pointer to a value type (struct instances) that was allocated with "automatic storage" (to borrow from C++ terminology). If you need to share value types, you need to wrap them, at some convenient level, in a reference type (class instances).

这意味着,通常来说,您不能存储一个指向值类型(struct实例)的指针,该值类型被分配给“自动存储”(借用c++术语)。如果您需要共享值类型,那么您需要在一个引用类型(类实例)中以某种方便的级别包装它们。

The most generic you could get would be to use a pair of closures, one that returns the value and another one that sets it. However, there's probably a less generic but more useful way to do it for your specific case.

最通用的方法是使用一对闭包,一个返回值,另一个设置值。但是,对于特定的情况,可能有一种不太通用但更有用的方法。

#1


1  

In Swift, the only pointers that you can reliably store are those allocated with UnsafeMutablePointer.allocate. The pointers that you can get from the address-of operator and withUnsafeMutablePointer are cheats and they are only valid for a short time; using them beyond that point will have unpredictable results.

在Swift中,惟一可以可靠存储的指针是那些使用unsafemutablepointer. allocation分配的指针。你可以从寻址操作符和unsafemutablepointer中获得的指针是欺骗,它们只在短时间内有效;超过这一点使用它们将产生不可预测的结果。

This means that, generally speaking, you can't store a pointer to a value type (struct instances) that was allocated with "automatic storage" (to borrow from C++ terminology). If you need to share value types, you need to wrap them, at some convenient level, in a reference type (class instances).

这意味着,通常来说,您不能存储一个指向值类型(struct实例)的指针,该值类型被分配给“自动存储”(借用c++术语)。如果您需要共享值类型,那么您需要在一个引用类型(类实例)中以某种方便的级别包装它们。

The most generic you could get would be to use a pair of closures, one that returns the value and another one that sets it. However, there's probably a less generic but more useful way to do it for your specific case.

最通用的方法是使用一对闭包,一个返回值,另一个设置值。但是,对于特定的情况,可能有一种不太通用但更有用的方法。