正则表达式匹配特定的模式

Please help me correct this regular expression in C# to match/validate only when the following is true:

请帮助我更正c#中的这个正则表达式，只有当以下内容为真时才匹配/验证:

Always starts with da/
总是从da /开始
At least one single character after da/
da/之后至少有一个字符
Only non capitals are allowed, range from a-z (both included)
只允许非大写字母，范围从a-z(包括)
digits 0-9 allowed
数字0 - 9允许
dashes are allowed (-)
允许破折号(-)

This is what I have, but it's not working:

这就是我所拥有的，但它不起作用:

/^da/+[a-z0-9+-]+$/

Example of accepted string that will validate the regular expression:

用于验证正则表达式的可接受字符串示例:

da/this-will-validate-correct-1

2 个解决方案

#1

Your regex allows 1 or more / after da and the + inside the character class allowed + symbols.

您的正则表达式允许一个或多个/在da和+内的字符类允许+符号。

Judging by the requirements, you just need

根据需求判断，您只需要

^da/[a-z0-9-]+$

See the regex demo

看到regex演示

The + after the character class [a-z0-9+-] requires at least 1 character after da/.

字符类[a-z0-9+-]后面的+在da/之后至少需要一个字符。

Regex.IsMatch("da/this-will-validate-correct-1", @"^da/[a-z0-9-]+$")

See the C# demo

查看演示c#

Pattern explanation:

模式说明:

^ - start of string
^ -字符串的开始
da/ - a literal string of characters da/
da/ -一个字串字符da/。
[a-z0-9-]+ - 1 or more characters from a-z and 0-9 ranges or a -
[a-z0-9-]+ - 1或以上a-z和0-9的字符或a-
$ - end of string.
$ -字符串的末端。

#2

you can try this ^da/[a-z0-9\-]+$

你可以试试这个^ da / a-z0-9 \[-]+ $

#1