使用if具有多个数组值PHP [重复]

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PHP parse/syntax errors; and how to solve them? 16 answers

PHP解析/语法错误;以及如何解决它们? 16个答案

I have a string which will be added from the user

我有一个字符串,将从用户添加

I will separate the string into an array I'll separate each character alone

我将字符串分成一个数组,我将单独分隔每个字符

then I want to find a specific word which is

那么我想找一个特定的词

if(

this is my code but I got an error

这是我的代码,但我收到了一个错误

$StingFromTheUser = 'public class a
{
    if(int i=0; i<10; i++)
    {
        //any thing
    }
} '//end of the string

I separate it using this code which is correct

我使用这个正确的代码分开它

$arr = str_split($StringFromTheUser);

Now I want to find if the code has if statement or not so I'm going to search for the word

现在我想找到代码是否有if语句,所以我要搜索这个单词

if(

here is my code

这是我的代码

for($i=0; $i<count($arr)-2; $i++)
{
    if(arr[$i]=='i' && arr[$i+1]=='f' && arr[$i+2]=='(')
    {
        echo $arr[$i].$arr[$i+1].$arr[$i+2];
    }
}

but unfortunately I got this error

但不幸的是我收到了这个错误

Parse error: syntax error, unexpected '[' in /fileName.php on line 331

解析错误:语法错误,第331行的/fileName.php中的意外'['

2 个解决方案

#1

 if($arr[$i]=='i' && $arr[$i+1]=='f' && $arr[$i+2]=='(')

Use $ infront of arr

使用$ infront of arr

#2

you forget $ in your arr

你忘了你的arr

it would be

这将是

if($arr[$i]=='i' && $arr[$i+1]=='f' && $arr[$i+2]=='(')
   {
      echo $arr[$i].$arr[$i+1].$arr[$i+2];
   }

and you use if in for condition:-

并且你使用if in for condition: -

 for(int i=0; i<10; i++)
    {
        //any thing
    }

#1

 if($arr[$i]=='i' && $arr[$i+1]=='f' && $arr[$i+2]=='(')