只有在array1中存在键时，才使用array2重写array1中的值

I would like to set an associative array of default keys and values(array1); If an array is provided (array2) then all indexes from array1 will be overwritten by array2 where the keys match. Any additional keys in array2 wont be added to array1.

我想设置一个默认键和值的关联数组(array1);如果提供了一个数组(array2)，那么array1的所有索引都将被array2覆盖，其中的键匹配。array2中的任何附加键都不会被添加到array1。

One solution is to run a loop and do a array_key_exists like so.

一种解决方案是运行一个循环并像这样执行array_key_exists。

$new_array = $array1;

foreach ($array2 as $key => $value) {

    if(array_key_exists($key, $array1)){
        $new_array[$key] = $value; //overwrite default value
    } else {
        // new key, dont add 
    }
}

but is there a php function which does this already ?

但是有一个php函数已经这样做了吗?

the functions i have tries already dont give my the results i would like.

我已经尝试过的功能并没有给出我想要的结果。

    $array1 = array(
        'one' =>'one',
        'two' => 'two',
        'three' => 'three',
        'four' => 'four'
    );
    $array2 = array(
        'two' => '2',
        'four' => '4',
        'six' => '6',
    );

    var_dump($array1+$array2);
    array (size=5)
        'one' => string 'one' (length=3)
        'two' => string 'two' (length=3)
        'three' => string 'three' (length=5)
        'four' => string 'four' (length=4)
        'six' => string '6' (length=1)

    var_dump(array_merge($array1,$array2));
    array (size=5)
        'one' => string 'one' (length=3)
        'two' => string '2' (length=1)
        'three' => string 'three' (length=5)
        'four' => string '4' (length=1)
        'six' => string '6' (length=1)

    var_dump(array_replace($array1,$array2));
    array (size=5)
        'one' => string 'one' (length=3)
        'two' => string '2' (length=1)
        'three' => string 'three' (length=5)
        'four' => string '4' (length=1)
        'six' => string '6' (length=1)

The result i am looking for would be

我想要的结果是

    array (size=4)
        'one' => string 'one' (length=3)
        'two' => string '2' (length=1)
        'three' => string 'three' (length=5)
        'four' => string '4' (length=1)

1 个解决方案

#1

Take from 2nd array keys, present in 1st, and replace value in 1st

从2个数组键中取1，替换1

print_r(array_replace($array1, array_intersect_key($array2, $array1)));