将javascript数组值0更改为null值

I have a few arrays that are laid out like so:

我有一些像这样布局的数组：

var row1 = [4,6,4,0,9];
var row2 = [5,2,0,8,1];
var row3 = [2,0,3,1,6];

I want to replace any values that have 0 with a null value. so they would look like:

我想用0替换任何值为0的值。所以它们看起来像：

var row1 = [4,6,4,,9];
var row2 = [5,2,,8,1];
var row3 = [2,,3,1,6];

Any ideas? Basically what I'm trying to do is loop through each value of the array, check to see if it equals 0, and if so replace it with a null value.

有任何想法吗？基本上我要做的是循环遍历数组的每个值，检查它是否等于0，如果是这样，用空值替换它。

Thanks in advance.

提前致谢。

3 个解决方案

#1

You could do this:

你可以这样做：

var row1 = [4,6,4,0,9];
var row2 = [5,2,0,8,1];
var row3 = [2,0,3,1,6];

var arrRows = [row1, row2, row3];

for (var i = 0; i < arrRows.length; i++) {
    for (var j = 0; j < arrRows[i].length; j++) {
        if (arrRows[i][j] == 0) {
            arrRows[i][j] = null;
        }
    }
}

Demo: http://jsfiddle.net/npYr2/

演示：http：//jsfiddle.net/npYr2/

#2

You can use Array.prototype.map:

您可以使用Array.prototype.map：

row1 = row1.map(function(val, i) {
    return val === 0 ? null : val;
});

http://jsfiddle.net/6Mz38/

#3

Another possibility is the following

另一种可能性如下

var rows = [row1, row2, row3];

rows = rows.map(function(x){ return x.map(function(y){ return y === 0? null: y})});

#1