请帮助传递多维数组。

I'm writing a simple test program to pass multidimensional arrays. I've been struggling to get the signature of the callee function.

我正在编写一个简单的测试程序来通过多维数组。我一直在努力得到callee函数的签名。

The code I have:

我的代码:

void p(int (*s)[100], int n) { ... }

...

{
  int s1[10][100], s2[10][1000];
  p(s1, 100);
}

This code appears to work, but is not what I intended. I want the function p to be oblivious whether the range of values is either 100 or 1000, but should know there are 10 pointers (by use of function signature).

这段代码似乎可以工作，但不是我想要的。我希望函数p能够忽略值的范围是100还是1000，但是应该知道有10个指针(通过函数签名)。

As a first attempt:

第一次尝试:

void p(int (*s)[10], int n) // n = # elements in the range of the array

and as a second:

作为第二:

void p(int **s, int n) // n = # of elements in the range of the array

But to no avail can I seem to get these to work correctly. I don't want to hardcode the 100 or 1000 in the signature, but instead pass it in, keeping in mind there will always be 10 arrays.

但是，我似乎无法使它们正常工作。我不想在签名中硬编码100或1000，而是把它传递进来，记住总是会有10个数组。

Obviously, I want to avoid having to declare the function:

显然，我想避免必须声明函数:

void p(int *s1, int *s2, int *s3, ..., int *s10, int n)

FYI, I'm looking at the answers to a similar question but still confused.

顺便说一下，我正在看一个类似问题的答案，但还是很困惑。

2 个解决方案

#1

You need to transpose your arrays for this to work. Declare

你需要对数组进行变换才能让它工作。声明

int s1[100][10];
int s2[1000][10];

Now, you can pass these to a function like this:

现在，你可以把这些传递给这样的函数:

void foo(int (*s)[10], int n) {
    /* various declarations */
    for (i = 0; i < n; i++)
        for (j = 0; j < 10; j++)
            s[i][j] += 1
}

Because of the way the C type system works, an array argument can only be "flexible" in the sense you want in its left-most index.

由于C类型系统的工作方式，数组参数只能在最左索引中“灵活”。

#2

You could also create a struct for the matrix and pass it to the function p

你也可以为矩阵创建一个结构体并将它传递给函数p

struct Matrix{
     int **array;
     int n;
     int m;
};


void p(Matrix *k){
     length=k->m;
     width=k->n;
     firstElement=k->array[0][0];
}

#1