如何在Numpy中使用savetxt的两个先行空格?

时间：2022-08-01 21:22:16

I am preparing a file in Python to be read in Fortran. The file looks like this:

我正在用Python准备一个用Fortran读取的文件。文件如下:

 0.0000000E+00  0.0000000E+00  0.0000000E+00  1.5000000E-01
 1.0193980E-02  0.0000000E+00  0.0000000E+00  1.5000000E-01
 2.0387960E-02  0.0000000E+00  0.0000000E+00  1.5000000E-01
 3.0581940E-02  0.0000000E+00  0.0000000E+00  1.5000000E-01
 4.0775920E-02  0.0000000E+00  0.0000000E+00  1.5000000E-01
 5.0969900E-02  0.0000000E+00  0.0000000E+00  1.5000000E-01
 6.1163880E-02  0.0000000E+00  0.0000000E+00  1.5000000E-01
 7.1357860E-02  0.0000000E+00  0.0000000E+00  1.5000000E-01
 8.1551840E-02  0.0000000E+00  0.0000000E+00  1.5000000E-01

it starts with one leading blank space and then the spacing between columns becomes 2 blanks. The Fortran executable that I have (no access to the source code), reads and writes E15.7 format which means I need two leading blanks like the following:

它从一个前导空格开始，然后列之间的间隔变成两个空格。我拥有的Fortran可执行文件(无法访问源代码)，读取和编写E15.7格式，这意味着我需要两个主要空格，如下所示:

  0.0000000E+00  0.0000000E+00  0.0000000E+00  1.5000000E-01
  1.0193980E-02  0.0000000E+00  0.0000000E+00  1.5000000E-01
  2.0387960E-02  0.0000000E+00  0.0000000E+00  1.5000000E-01
  3.0581940E-02  0.0000000E+00  0.0000000E+00  1.5000000E-01
  4.0775920E-02  0.0000000E+00  0.0000000E+00  1.5000000E-01
  5.0969900E-02  0.0000000E+00  0.0000000E+00  1.5000000E-01
  6.1163880E-02  0.0000000E+00  0.0000000E+00  1.5000000E-01
  7.1357860E-02  0.0000000E+00  0.0000000E+00  1.5000000E-01
  8.1551840E-02  0.0000000E+00  0.0000000E+00  1.5000000E-01

My python script that produce the file is like this:

生成该文件的python脚本如下:

np.savetxt(fpath, data, fmt='%14.7E')

If I use fmt='%15.7E' the leading blanks becomes two but the rest of the spaces will be 3.

如果我使用fmt='%15.7E'，那么前面的空格将变成2，但其余的空格将是3。

1 个解决方案

#1

2  

With a bit more involved format string you can do that like:

使用稍微复杂一点的格式字符串，您可以这样做:

Code:

np.savetxt(fpath, data, fmt=' %14.7E' * data.shape[1])

Test Code:

import numpy as np
fpath = 'test_data'
data = np.array([[1.0, 1.1, 12.0]])
np.savetxt(fpath, data, fmt=' %14.7E' * data.shape[1])

Results:

  1.0000000E+00  1.1000000E+00  1.2000000E+01

#1

2  

With a bit more involved format string you can do that like:

使用稍微复杂一点的格式字符串，您可以这样做:

Code:

np.savetxt(fpath, data, fmt=' %14.7E' * data.shape[1])

Test Code:

import numpy as np
fpath = 'test_data'
data = np.array([[1.0, 1.1, 12.0]])
np.savetxt(fpath, data, fmt=' %14.7E' * data.shape[1])

Results:

  1.0000000E+00  1.1000000E+00  1.2000000E+01
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