C ++如何将数组int [10] push_back转换为std :: vector ？

#include <vector>
using namespace std;

vector<int[60]> v;
int s[60];
v.push_back(s);

This code in Visual Studio 2015 community report a compile error:

Visual Studio 2015社区中的此代码报告编译错误:

Error (active) no instance of overloaded function "std::vector<_Ty, _Alloc>::push_back [with _Ty=int [60], _Alloc=std::allocator]" matches the argument list

错误(活动)没有重载函数的实例“std :: vector <_Ty,_Alloc> :: push_back [with _Ty = int [60],_ Alloc = std :: allocator]”匹配参数列表

Error C2664 'void std::vector>::push_back(const int (&)[60])': cannot convert argument 1 from 'int' to 'int (&&)[60]'

错误C2664'void std :: vector> :: push_back(const int(&)[60])':无法将参数1从'int'转换为'int(&&)[60]'

3 个解决方案

#1

Use std::array, instead:

改为使用std :: array:

#include <vector>
#include <array>

using namespace std;

int main()
{
    vector<array<int, 10>> v;
    array<int, 10> s;
    v.push_back(s);
    return 0;
}

But I also have to question the purpose of having a vector containing an array. Whatever is the underlying reason for that, there's likely to be a better way of accomplishing the same goals.

但我还要质疑包含数组的向量的目的。无论是什么原因,都可能有更好的方法来实现相同的目标。

#2

You can do it like this:

你可以这样做:

#include <iostream>
#include <vector>

int main()
{
    int t[10] = {1,2,3,4,5,6,7,8,9,10};

    std::vector<int*> v;

    v.push_back(t);

    std::cout << v[0][4] << std::endl;

   return 0;
}

To be more specific in this solution you do not actually store values of array t into vector v you just store pointer to array (and to be even more specific to first element of array)

更具体地说,在这个解决方案中,你实际上并没有将数组t的值存储到向量v中,只是存储指向数组的指针(并且更具体地说是数组的第一个元素)

#3

I am not sure are you saying initialize a vector from an array, if yes here is a way to do it using vector's constructor:

我不确定你是说从数组初始化一个向量,如果是,这是使用向量的构造函数执行它的方法:

int s[] = {1,2,3,4};
vector<int> v (s,  s + sizeof(s)/sizeof(s[0]));

#1