Java删除数组中的多个整数

I have an array of integers.

我有一个整数数组。

18 9 22 34 11 8 15 13 2 55

and a separate integer. 12
How can I remove all the integer element that is less than 12 so the resulting array will be

和一个单独的整数。 12如何删除小于12的所有整数元素,以便生成数组

18 22 34 15 13 55

Thank you in advance.

先感谢您。

2 个解决方案

#1

int count = 0; //initialize count
for(int i = 0; i < arrayname.length; i++){
    if(arrayname[i] > 12){
        count++; //iterate original array, getting number of integers greater than 12
    }
}


int[] newarray = [count]; //initialize new array to this number
count = 0; //reinitialize count to begin at first element in new array
for(int i = 0; i < arrayname.length; i++){
    if(arrayname[i] > 12){
        newarray[count] = arrayname[i]; //set each element >12 in original to next element in new array
        count++; //move through new array
    }
}

Hope this helps :-)

希望这可以帮助 :-)

#2

Since this is clear homework, I show my disagreement and down vote with my answer

由于这是明确的家庭作业,我用我的答案表明我的不同意见和投票

In Java 8 :

在Java 8中:

Code:

    List<Integer> list1 = Arrays.asList(18, 9, 22 ,34 ,11 ,8 ,15 ,13, 2 ,55);
    list1.stream()
         .filter( i -> i > 12)
         .forEach( i -> System.out.print(i + " "));

Output: 18 22 34 15 13 55

产出:18 22 34 15 13 55

#1

int count = 0; //initialize count
for(int i = 0; i < arrayname.length; i++){
    if(arrayname[i] > 12){
        count++; //iterate original array, getting number of integers greater than 12
    }
}


int[] newarray = [count]; //initialize new array to this number
count = 0; //reinitialize count to begin at first element in new array
for(int i = 0; i < arrayname.length; i++){
    if(arrayname[i] > 12){
        newarray[count] = arrayname[i]; //set each element >12 in original to next element in new array
        count++; //move through new array
    }
}