Already tried the suggested JSONPath option, but it seems the JSONExtractor only recognizes root level. In my case I have to deal with a nested json-structure, with an array as well (see example below). Any options for extracting this without multiple intermediate files?
已经尝试了建议的JSONPath选项,但似乎JSONExtractor只识别根级别。在我的情况下,我必须处理嵌套的json结构,也有一个数组(见下面的例子)。没有多个中间文件的任何提取选项?
"relation": {
"relationid": "123456",
"name": "relation1",
"addresses": {
"address": [{
"addressid": "1",
"street": "Street 1",
"postcode": "1234 AB",
"city": "City 1"
},
{
"addressid": "2",
"street": "Street 2",
"postcode": "5678 CD",
"city": "City 2"
}]
}}
SELECT relationid, addressid, street, postcode, city ?
SELECT relationid,addressid,street,postcode,city?
1 个解决方案
#1
10
After fixing your JSON fragment to:
将JSON片段修复为:
{
"relation": {
"relationid": "123456",
"name": "relation1",
"addresses": {
"address": [{
"addressid": "1",
"street": "Street 1",
"postcode": "1234 AB",
"city": "City 1"
}, {
"addressid": "2",
"street": "Street 2",
"postcode": "5678 CD",
"city": "City 2"
}]
}
}
}
and putting it into a file, the following script will get you what you want. Note that you need to navigate down the structure to carry along the higher level items and once you encounter an array, you CROSS APPLY EXPLODE
it if you only need those that have the array, or OUTER APPLY EXPLODE it if you want rows with missing arrays.
并将其放入文件中,以下脚本将为您提供所需的内容。请注意,您需要向下导航结构以携带更高级别的项目,并且一旦遇到数组,如果您只需要具有该数组的那些,则CROSS APPLY EXPLODE,如果您想要缺少数组的行,则使用OUTER APPLY EXPLODE 。
DECLARE @input string = @"/temp/*.json";
REFERENCE ASSEMBLY [Newtonsoft.Json];
REFERENCE ASSEMBLY [Microsoft.Analytics.Samples.Formats];
@json =
EXTRACT relationid int,
name string,
addresses string
FROM @input
USING new Microsoft.Analytics.Samples.Formats.Json.JsonExtractor("relation");
@relation =
SELECT relationid,
name,
Microsoft.Analytics.Samples.Formats.Json.JsonFunctions.JsonTuple(addresses)["address"] AS address_array
FROM @json;
@addresses =
SELECT relationid,
name,
Microsoft.Analytics.Samples.Formats.Json.JsonFunctions.JsonTuple(address) AS address
FROM @relation
CROSS APPLY
EXPLODE (Microsoft.Analytics.Samples.Formats.Json.JsonFunctions.JsonTuple(address_array).Values) AS A(address);
@result =
SELECT relationid,
name,
address["addressid"]AS addressid,
address["street"]AS street,
address["postcode"]AS postcode,
address["city"]AS city
FROM @addresses;
OUTPUT @result
TO "/users/temp/st_out.csv"
USING Outputters.Csv();
#1
10
After fixing your JSON fragment to:
将JSON片段修复为:
{
"relation": {
"relationid": "123456",
"name": "relation1",
"addresses": {
"address": [{
"addressid": "1",
"street": "Street 1",
"postcode": "1234 AB",
"city": "City 1"
}, {
"addressid": "2",
"street": "Street 2",
"postcode": "5678 CD",
"city": "City 2"
}]
}
}
}
and putting it into a file, the following script will get you what you want. Note that you need to navigate down the structure to carry along the higher level items and once you encounter an array, you CROSS APPLY EXPLODE
it if you only need those that have the array, or OUTER APPLY EXPLODE it if you want rows with missing arrays.
并将其放入文件中,以下脚本将为您提供所需的内容。请注意,您需要向下导航结构以携带更高级别的项目,并且一旦遇到数组,如果您只需要具有该数组的那些,则CROSS APPLY EXPLODE,如果您想要缺少数组的行,则使用OUTER APPLY EXPLODE 。
DECLARE @input string = @"/temp/*.json";
REFERENCE ASSEMBLY [Newtonsoft.Json];
REFERENCE ASSEMBLY [Microsoft.Analytics.Samples.Formats];
@json =
EXTRACT relationid int,
name string,
addresses string
FROM @input
USING new Microsoft.Analytics.Samples.Formats.Json.JsonExtractor("relation");
@relation =
SELECT relationid,
name,
Microsoft.Analytics.Samples.Formats.Json.JsonFunctions.JsonTuple(addresses)["address"] AS address_array
FROM @json;
@addresses =
SELECT relationid,
name,
Microsoft.Analytics.Samples.Formats.Json.JsonFunctions.JsonTuple(address) AS address
FROM @relation
CROSS APPLY
EXPLODE (Microsoft.Analytics.Samples.Formats.Json.JsonFunctions.JsonTuple(address_array).Values) AS A(address);
@result =
SELECT relationid,
name,
address["addressid"]AS addressid,
address["street"]AS street,
address["postcode"]AS postcode,
address["city"]AS city
FROM @addresses;
OUTPUT @result
TO "/users/temp/st_out.csv"
USING Outputters.Csv();