为数组的指针赋值

I'm using a pointer to an array in a function that reference a array in the main function. I've completely forgotten about pointers. I'm trying:

我在函数中使用指向数组的指针,该函数引用main函数中的数组。我完全忘记了指针。我尝试着:

    int main(void){
   int length;
   char punct;
   string password;

   cout << "Enter length of passwords: " << endl;
   cin >> length;
   char array[length];

   //run random password generator here                                          

    password = generator(*array);

    cout << "Here is your password: " << endl;
    return 0;
    }

    char* generator(char* array){
    int counter = 0;
    int random;
   while(counter <= 8){
    random = rand() % 200 + 32;
     if(random >= 32 && random != 95 && random != 127)
     char
   }
   return result;
   }

I'm getting errors but can't quite put a finger on what I'm screwing up here.

我收到了错误,但是我不能完全理解我在这里搞砸了什么。

  He are the errors (sorry for not including them in the initial post):
  password.cpp:7:14: error: two or more data types in declaration of ‘main’
  password.cpp: In function ‘char* generator(char*)’:
  password.cpp:31:3: error: expected unqualified-id before ‘}’ token
  password.cpp:32:10: error: ‘result’ was not declared in this scope

thanks for any help.

谢谢你的帮助。

2 个解决方案

#1

First of all,i can tell you many reasons for the errors If you are using the exact program to compile,

首先,我可以告诉你许多错误的原因如果你使用确切的程序进行编译,

length does not has an initialization

长度没有初始化
The signature of the function otherFunction varies between where it is called and its definition

函数otherFunction的签名在调用它的位置和它的定义之间变化
*array[i] does not make any sense in the definition of otherFunction since array[i] itself is a dereference operation

* array [i]在otherFunction的定义中没有任何意义,因为array [i]本身是一个解除引用操作

I think this is what you are expecting

我想这就是你所期待的

    char* otherFunction(char[] array)
    {
        array[0] = 'x';
        array[1] = 'y';
        return array;
    }
    int main()
    {
       int length =5;
       char array[length] = "array";
       printf("%s Before otherFunction",array);
       char* newArray = otherFunction(array);
       printf("%s After otherFunction",array);
    }

O/P:

array Before otherFunction
xyray After otherFunction

#2

You seem to display confusion in regards to pointer fundamentals. There are six erroneous lines in your eight lines of code. Which book are you reading?

你似乎在指针基础方面表现出混乱。你的八行代码中有六条错误的行。你正在读哪本书?

#1