循环遍历数组中的特定索引

I have a table with products and it's variants.

我有一个产品表和它的变种。

Each one has an index on the table, for instance:

每个表都有一个索引,例如:

[0] Product 1

[1] Variant 1

[2] Variant 2

[3] Product 2

etc..

I've assigned to an associative array all the variant's indexes along with their value, for instance:

我已将所有变体索引及其值分配给关联数组,例如:

[1] Variant 1 : 13

[2] Variant 2 : 15

[18] Variant 3: 32

Now I want to loop through the table using only the indexes I got on my array.

现在我想只使用我在数组上得到的索引遍历表。

Is there a way to loop through an element using specific indexes? ( So I don't have to loop through the whole thing and execute what I want whenever it matches ). Something similar to this pseudocode:

有没有办法使用特定索引循环元素? (所以我不必遍历整个事情并在匹配时执行我想要的东西)。与此伪代码类似的东西:

loop through my_table on index = [1,2,18]

循环遍历my_table on index = [1,2,18]

Edit for Joseph Marikle:

编辑Joseph Marikle:

The code part for the array is this:

数组的代码部分是这样的:

var variants_index = [];
  $.each($('.variant'),function(){
    variants_index[$(this).index()] = $(this).find('td').eq(1).text();
  });

typing typeof(variants_index) we get: object and typing the var in the console, we get Array and, typing Array.isArray(variants_index) we get true

输入typeof(variants_index)我们得到:对象并在控制台中键入var,我们得到数组,然后输入Array.isArray(variants_index)我们得到的

2 个解决方案

#1

You can loop through your array of indices that you are interested in and use their values as an index to your array containing product info.

您可以遍历您感兴趣的索引数组,并将它们的值用作包含产品信息的数组的索引。

var indexToCheck = [1,2,18];

for(var i = 0; i < indexToCheck.length; i++){
  var productInfo = myProducts[indexToCheck[i]];
}

#2

loop through my_table on index = [1,2,8] (changed the 18 to 8 for simplicity)

在index = [1,2,8]上循环遍历my_table(为简单起见,将18更改为8)

Since that's the core of the problem, let's try to solve it.

由于这是问题的核心,让我们试着解决它。

index = [1,2,8]
my_table = [5,4,6,7,3,8,2,9,0,1]
for (i=0;i<index.length;i++){
    console.log(my_table[index[i]]);
}

This would get the numbers from "index" as use them as indexes to access positions in my_table

这将使“index”中的数字用作索引来访问my_table中的位置

#1