I need an Array with username and password. The method containing the array needs to return it. I tried the following code but android studio is showing and error when I tried to access the array from another method:
我需要一个用户名和密码的数组。包含数组的方法需要返回它。我尝试了以下代码,但是android studio在尝试从另一种方法访问数组时显示错误:
public class MainActivity extends Activity {
private static Boolean log_status;
public String[] credentials () {
String Username;
String Password;
String login_data;
EditText editText = (EditText) findViewById(R.id.username);
EditText editPass = (EditText) findViewById(R.id.password);
Username = editText.getText().toString();
Password = editPass.getText().toString();
String[] log_data= new String[1];
log_data[0]= Username;
log_data[1]=Password;
return log_data;
}
How can I make the log_data
array be accessed by another method? Does my code return an array?
如何让另一个方法访问log_data数组?我的代码是否返回一个数组?
4 个解决方案
#1
0
How can you access first element of array which is limited to 1
如何访问数组中第一个被限制为1的元素
String[] log_data= new String[1];
log_data[0]= Username;
log_data[1]=Password;
Increase the size of the array to 2
将数组的大小增加到2
String[] log_data= new String[2];
log_data[0]= Username;
log_data[1]=Password;
#2
0
String[] log_data= new String[1];
log_data[0]= Username;
log_data[1]=Password;
Your array size is just 1, not 2.
数组大小是1,而不是2。
Try changing
试着改变
String[] log_data= new String[2];
Also, if it doesn't solve, can you tell exact error message you are getting ?
而且,如果它不能解决问题,你能告诉你确切的错误信息吗?
#3
0
You made a few mistakes, please try this.
你犯了几个错误,请试试这个。
EditText password,username;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.first);
password = (EditText)findViewById(R.id.passWord);
username = (EditText)findViewById(R.id.userName);
}
public String[] LogInfo () {
String passWord = password.getText().toString();
String userName = username.getText().toString();
String[] log_data= new String[2];
log_data[0] = passWord;
log_data[1] = userName;
return log_data;
}
#4
0
String[] log_data= new String[1];
creates a Vector with 1 dimension, so I think it should be: String[] log_data= new String[2];
String[]log_data =新的字符串[1];创建一个一维的向量,所以我认为应该是:String[] log_data= new String[2];
#1
0
How can you access first element of array which is limited to 1
如何访问数组中第一个被限制为1的元素
String[] log_data= new String[1];
log_data[0]= Username;
log_data[1]=Password;
Increase the size of the array to 2
将数组的大小增加到2
String[] log_data= new String[2];
log_data[0]= Username;
log_data[1]=Password;
#2
0
String[] log_data= new String[1];
log_data[0]= Username;
log_data[1]=Password;
Your array size is just 1, not 2.
数组大小是1,而不是2。
Try changing
试着改变
String[] log_data= new String[2];
Also, if it doesn't solve, can you tell exact error message you are getting ?
而且,如果它不能解决问题,你能告诉你确切的错误信息吗?
#3
0
You made a few mistakes, please try this.
你犯了几个错误,请试试这个。
EditText password,username;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.first);
password = (EditText)findViewById(R.id.passWord);
username = (EditText)findViewById(R.id.userName);
}
public String[] LogInfo () {
String passWord = password.getText().toString();
String userName = username.getText().toString();
String[] log_data= new String[2];
log_data[0] = passWord;
log_data[1] = userName;
return log_data;
}
#4
0
String[] log_data= new String[1];
creates a Vector with 1 dimension, so I think it should be: String[] log_data= new String[2];
String[]log_data =新的字符串[1];创建一个一维的向量,所以我认为应该是:String[] log_data= new String[2];