I have a file contained within a directory in a classpath. It looks like this pl/shenlon/io/gui/appData/file.txt. Now, when I try to convert it to a File and read with this code:
我有一个包含在类路径目录中的文件。它看起来像这个pl/shenlon/io/gui/appData/file.txt。现在，当我试着把它转换成一个文件，并阅读这个代码:
File cityNamesFile = new File(ClassLoader.getSystemResource("pl/shenlon/io/gui/appData/list.txt").toURI());
Scanner cns = new Scanner(cityNamesFile);
I get the following:-
我得到以下:-
error - java.lang.IllegalArgumentException: URI is not hierarchical.
错误——. lang。IllegalArgumentException: URI不是分层的。
How can I fix this problem?
我如何解决这个问题?
2 个解决方案
#1
7
If your calling class is itself in the same package as the text file, just use :
如果您的调用类本身与文本文件在同一个包中，则只需使用:
InputStream is = getClass().getResourceAsStream("list.txt");
Scanner cns = new Scanner(is);
#2
6
Replace
取代
File cityNamesFile = new File(ClassLoader.getSystemResource("pl/shenlon/io/gui/appData/list.txt").toURI());
with
与
File cityNamesFile = new File(Thread.currentThread().getContextClassLoader().getResource("pl/shenlon/io/gui/appData/list.txt").getFile());
#1
7
If your calling class is itself in the same package as the text file, just use :
如果您的调用类本身与文本文件在同一个包中，则只需使用:
InputStream is = getClass().getResourceAsStream("list.txt");
Scanner cns = new Scanner(is);
#2
6
Replace
取代
File cityNamesFile = new File(ClassLoader.getSystemResource("pl/shenlon/io/gui/appData/list.txt").toURI());
with
与
File cityNamesFile = new File(Thread.currentThread().getContextClassLoader().getResource("pl/shenlon/io/gui/appData/list.txt").getFile());