问题描述
Example1: x = 123, return 321
Example2: x = -123, return -321
原题链接: https://leetcode.com/problems/reverse-integer/
解决方案
public int reverse(int x) {
long res = 0; //need to consider the overflow problem
while(x != 0){
res = res * 10 + x % 10; // -11%10 = -1
if(res > Integer.MAX_VALUE || res < Integer.MIN_VALUE){
return 0;
}
x = x/10;
}
return (int)res;
}