Sql中Rank排名函数

时间:2020-12-10 19:56:02

A.对分区中的行进行排名

以下示例按照数量对指定清单位置的清单中的产品进行了排名。

结果集按 LocationID 分区并在逻辑上按 Quantity 排序。

注意,产品 494 和 495 具有相同的数量。 因为它们是关联的,所以两者均排名第一。

 
USE AdventureWorks2012;
GO
SELECT i.ProductID, p.Name, i.LocationID, i.Quantity ,
RANK() OVER (PARTITION BY i.LocationID ORDER BY i.Quantity DESC) AS Rank
FROM Production.ProductInventory AS i
INNER JOIN Production.Product AS p ON i.ProductID = p.ProductID
WHERE i.LocationID BETWEEN 3 AND 4
ORDER BY i.LocationID;
GO

下面是结果集:

 
 
ProductID   Name                   LocationID   Quantity Rank
----------- ---------------------- ------------ -------- ----
494 Paint - Silver 3 49 1
495 Paint - Blue 3 49 1
493 Paint - Red 3 41 3
496 Paint - Yellow 3 30 4
492 Paint - Black 3 17 5
495 Paint - Blue 4 35 1
496 Paint - Yellow 4 25 2
493 Paint - Red 4 24 3
492 Paint - Black 4 14 4
494 Paint - Silver 4 12 5
(10 row(s) affected)

B.对结果集中的所有行排名

下面的示例返回按薪金排名的前十名员工。 因为未指定 PARTITION BY 子句,所以,RANK 函数应用于结果集中的所有行。

 
 
USE AdventureWorks2012
SELECT TOP(10) BusinessEntityID, Rate,
RANK() OVER (ORDER BY Rate DESC) AS RankBySalary
FROM HumanResources.EmployeePayHistory AS eph1
WHERE RateChangeDate = (SELECT MAX(RateChangeDate)
FROM HumanResources.EmployeePayHistory AS eph2
WHERE eph1.BusinessEntityID = eph2.BusinessEntityID)
ORDER BY BusinessEntityID;

下面是结果集:

 
 
BusinessEntityID Rate                  RankBySalary
---------------- --------------------- --------------------
1 125.50 1
2 63.4615 4
3 43.2692 8
4 29.8462 19
5 32.6923 16
6 32.6923 16
7 50.4808 6
8 40.8654 10
9 40.8654 10
10 42.4808 9