判断闰年,用三种不同的方法交换两个数的值

时间:2021-02-22 19:30:16

3. 判断1000年---2000年之间的闰年

#define _CRT_SECURE_NO_WARNINGS 1

#include<stdio.h>

int main()

{

int year = 0;

int count = 0;

for (year = 1000; year <= 2000; year++)

{

if (year % 4 == 0)

{

if (year % 100 != 0)

{

printf("%d ", year);

count++;

}

}

if (year % 400 == 0)

{

printf("%d ", year);

count++;

}

}

printf("\ncount=%d", count);

system("pause");

return 0;

}

4. 给定两个整形变量的值,将两个值的内容进行交换。(或不允许创建临时变量){异或的效率低,可读性差,还不如加减}

int main()

{

int a = 0;

int b = 0;

scanf("%d%d", &a, &b);

a = a^b;

b = a^b;

a = a^b;

//a = a + b;

//b = a - b;

//b = a - b;

/*int tmp = 0;

tmp = a;

a = b;

b = tmp;*/

printf("%d %d", a, b);

system("pause");

return 0;

}