Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below.
For example, given the following triangle
[ [2], [3,4], [6,5,7], [4,1,8,3] ]
The minimum path sum from top to bottom is 11
(i.e., + + + = 11).
Note:
Bonus point if you are able to do this using only O(n) extra space, where n is the total number of rows in the triangle.
给定一个三角形,求最小路径。每层只能选一个整数,上一层和下一层的数必须是相邻的。
class Solution { public: int minimumTotal(vector<vector<int>>& triangle) { for (int i = triangle.size() - 2; i >= 0; --i) { for (int j = 0; j < triangle[i].size(); ++j) { triangle[i][j] += min(triangle[i + 1][j], triangle[i + 1][j + 1]); } } return triangle[0][0]; } };