I'm trying to find a command that would list all files (including hidden files), but must exclude the current directory and parent directory. Please help.
我正在尝试查找列出所有文件（包括隐藏文件）的命令，但必须排除当前目录和父目录。请帮忙。
$ ls -a \.\..
2 个解决方案
#1
15
Read ls(1) documentation (perhaps with man ls). At least, take the habit of trying
阅读ls（1）文档（也许与man ls）。至少，要养成尝试的习惯
ls --help
or better yet (since ls might be aliased, e.g. in your ~/.bashrc)
或更好（因为ls可能是别名，例如在你的〜/ .bashrc中）
/bin/ls --help
You'll get something starting with:
你会得到一些东西：
Usage: ls [OPTION]... [FILE]...
List information about the FILEs (the current directory by default).
Sort entries alphabetically if none of -cftuvSUX nor --sort is specified.
Mandatory arguments to long options are mandatory for short options too.
-a, --all do not ignore entries starting with .
-A, --almost-all do not list implied . and ..
--author with -l, print the author of each file
-b, --escape print C-style escapes for nongraphic characters
etc....
等等....
You want ls -A or better yet /bin/ls -A (without any additional argument such as .*)
你想要ls -A或更好的/ bin / ls -A（没有任何额外的参数，如。*）
#2
3
I have a situation where I want to remove a series of dot-directories. In my servers we mark directories for removal adding a dot and certain other text patterns (timestamp) for automated removal. Sometimes I need to do that manually.
我有一种情况，我想删除一系列的点目录。在我的服务器中，我们标记要删除的目录，添加一个点和某些其他文本模式（时间戳）以便自动删除。有时候我需要手动完成。
As I commented to Basile Starynkevitch's reply, when you use a globbing pattern like the one below the -A switch loses its function and works just as -a:
正如我对Basile Starynkevitch的回复所评论的那样，当你使用类似下面的一个模式时，-A开关失去了它的功能并且像-a一样工作：
runlevel0@ubuntu:~/scripts$ ls -1dA .*
.
..
.comparepp.sh.swp
It would most certainly give an error if I try to remove files as a user, but I just don't want to think what could happen as root (!)
如果我尝试以用户身份删除文件，它肯定会出错，但我只是不想想以root身份发生什么（！）
My approach in this case is:
我在这种情况下的方法是：
for dir in $(ls -1ad .* | tail -n +3) ; do rm -rfv $dir ; done
I tail out the 2 first line containing the dots as you can see. To tailor the answer to the question asked this would do the job:
我可以看到包含点的第一行2。为了定制问题的答案，这可以做到这一点：
ls -d1A .* | tail -n +3
#1
15
Read ls(1) documentation (perhaps with man ls). At least, take the habit of trying
阅读ls（1）文档（也许与man ls）。至少，要养成尝试的习惯
ls --help
or better yet (since ls might be aliased, e.g. in your ~/.bashrc)
或更好（因为ls可能是别名，例如在你的〜/ .bashrc中）
/bin/ls --help
You'll get something starting with:
你会得到一些东西：
Usage: ls [OPTION]... [FILE]...
List information about the FILEs (the current directory by default).
Sort entries alphabetically if none of -cftuvSUX nor --sort is specified.
Mandatory arguments to long options are mandatory for short options too.
-a, --all do not ignore entries starting with .
-A, --almost-all do not list implied . and ..
--author with -l, print the author of each file
-b, --escape print C-style escapes for nongraphic characters
etc....
等等....
You want ls -A or better yet /bin/ls -A (without any additional argument such as .*)
你想要ls -A或更好的/ bin / ls -A（没有任何额外的参数，如。*）
#2
3
I have a situation where I want to remove a series of dot-directories. In my servers we mark directories for removal adding a dot and certain other text patterns (timestamp) for automated removal. Sometimes I need to do that manually.
我有一种情况，我想删除一系列的点目录。在我的服务器中，我们标记要删除的目录，添加一个点和某些其他文本模式（时间戳）以便自动删除。有时候我需要手动完成。
As I commented to Basile Starynkevitch's reply, when you use a globbing pattern like the one below the -A switch loses its function and works just as -a:
正如我对Basile Starynkevitch的回复所评论的那样，当你使用类似下面的一个模式时，-A开关失去了它的功能并且像-a一样工作：
runlevel0@ubuntu:~/scripts$ ls -1dA .*
.
..
.comparepp.sh.swp
It would most certainly give an error if I try to remove files as a user, but I just don't want to think what could happen as root (!)
如果我尝试以用户身份删除文件，它肯定会出错，但我只是不想想以root身份发生什么（！）
My approach in this case is:
我在这种情况下的方法是：
for dir in $(ls -1ad .* | tail -n +3) ; do rm -rfv $dir ; done
I tail out the 2 first line containing the dots as you can see. To tailor the answer to the question asked this would do the job:
我可以看到包含点的第一行2。为了定制问题的答案，这可以做到这一点：
ls -d1A .* | tail -n +3