I have a string like the following "blaa...blup..blaaa...bla."
我有一个像下面的字符串“blaa ... blup..blaaa ... bla。”
Every part where there is more than one dot must be replaced by "_" but it must have the same amount as replaced chars.
必须用“_”替换每个有多个点的部分,但它必须与替换的字符具有相同的数量。
The string should result in: "bla___blup__blaaa___bla."
字符串应该导致:“bla___blup__blaaa___bla”。
Notice that the last dot is not replaced as it has not other dots "connected".
请注意,最后一个点未被替换,因为它没有其他点“已连接”。
I tried using following regex approach in powershell but I always get a legnth of 2 for the match regardless if there where 3 or more dots:
我尝试在powershell中使用以下正则表达式方法,但无论是否有3个或更多点,我总是得到匹配的第2个:
$string -replace '(.)\1+',("_"*'$&'.length)
Any ideas?
3 个解决方案
#1
7
You can use the \G anchor to glue a match to the previous.
您可以使用\ G锚点将匹配粘贴到上一个。
\.(?=\.)|\G(?!^)\.
-
\.(?=\.)match a period if another one is ahead. -
|\G(?!^)\.or replace period if there was a previous match (but not start)
\。(?= \。)匹配一个句号,如果另一个领先。
| \ G□\(^!)。或者如果之前有匹配(但不是开始)则替换句点
Replace with underscore. See demo at regexstorm
替换为下划线。请参阅regexstorm上的演示
#2
3
None of the languages and regex flavors I know allow you to evaluate the backreference numeric value "on the fly", you can only use it in the callback function. See Use a function in Powershell replace.
我所知道的语言和正则表达式都不允许您“动态”评估反向引用数值,您只能在回调函数中使用它。请参阅在Powershell替换中使用功能。
However, in this particular case, you can use the following regex:
但是,在这种特殊情况下,您可以使用以下正则表达式:
((?=\.{2})|(?!^)\G)\.
And replace with _.
并用_替换。
See the regex demo here.
请在此处查看正则表达式演示。
And the explanation:
并解释:
-
((?=\.{2})|(?!^)\G)- a boundary that either matches a location before 2 dots (with(?=\.{2})) or the end of the previous successful match (with(?!^)\G) -
\.- a literal dot.
((?= \。{2})|(?!^)\ G) - 与2点之前的位置匹配的边界(带(?= \。{2}))或上一次成功匹配的结束(用(?!^)\ G)
\。 - 一个字面点。
#3
3
You can use the following pattern:
您可以使用以下模式:
\.(?=\.)|(?<=\.)\.
And replace with _.
并用_替换。
The pattern simply looks for either a period that is preceded by a period or a period which is followed by a period:
该模式只查找以句点开头的句点或句点后跟句点:
-
\.(?=\.)- Matches a period which is followed by a period -
|- Or -
(?<=\.)\.- Matches a period which is preceded by a period
\。(?= \。) - 匹配句点,后跟句点
| - 要么
(?<= \)\。 - 匹配一个句点之前的句点
See the online demo.
请参阅在线演示。
#1
7
You can use the \G anchor to glue a match to the previous.
您可以使用\ G锚点将匹配粘贴到上一个。
\.(?=\.)|\G(?!^)\.
-
\.(?=\.)match a period if another one is ahead. -
|\G(?!^)\.or replace period if there was a previous match (but not start)
\。(?= \。)匹配一个句号,如果另一个领先。
| \ G□\(^!)。或者如果之前有匹配(但不是开始)则替换句点
Replace with underscore. See demo at regexstorm
替换为下划线。请参阅regexstorm上的演示
#2
3
None of the languages and regex flavors I know allow you to evaluate the backreference numeric value "on the fly", you can only use it in the callback function. See Use a function in Powershell replace.
我所知道的语言和正则表达式都不允许您“动态”评估反向引用数值,您只能在回调函数中使用它。请参阅在Powershell替换中使用功能。
However, in this particular case, you can use the following regex:
但是,在这种特殊情况下,您可以使用以下正则表达式:
((?=\.{2})|(?!^)\G)\.
And replace with _.
并用_替换。
See the regex demo here.
请在此处查看正则表达式演示。
And the explanation:
并解释:
-
((?=\.{2})|(?!^)\G)- a boundary that either matches a location before 2 dots (with(?=\.{2})) or the end of the previous successful match (with(?!^)\G) -
\.- a literal dot.
((?= \。{2})|(?!^)\ G) - 与2点之前的位置匹配的边界(带(?= \。{2}))或上一次成功匹配的结束(用(?!^)\ G)
\。 - 一个字面点。
#3
3
You can use the following pattern:
您可以使用以下模式:
\.(?=\.)|(?<=\.)\.
And replace with _.
并用_替换。
The pattern simply looks for either a period that is preceded by a period or a period which is followed by a period:
该模式只查找以句点开头的句点或句点后跟句点:
-
\.(?=\.)- Matches a period which is followed by a period -
|- Or -
(?<=\.)\.- Matches a period which is preceded by a period
\。(?= \。) - 匹配句点,后跟句点
| - 要么
(?<= \)\。 - 匹配一个句点之前的句点
See the online demo.
请参阅在线演示。