php中相同字符串中的多个字符串替换

I have the following string replacement problem and I am in quite a fix here

我有以下字符串替换问题,我在这里解决了很多问题

PFB the sample string

PFB样本字符串

$string = 'The quick sample_text_1 56 quick sample_text_2 78 fox jumped over the lazy dog.';

$patterns[0] = '/quick/';
$patterns[1] = '/quick/';
$patterns[2] = '/fox/';

$replacements[2] = 'bear';
$replacements[1] = 'black';
$replacements[0] = 'slow';

echo preg_replace($patterns, $replacements, $string);

I need to replace 'quick' depending on the numbers i send

我需要根据发送的号码替换“快速”

i.e if my input to a function is 56, the quick before 56 needs to be replaced with bear and if my input to a function is 78, the quick before 78 needs to be replaced with black

即如果我对函数的输入是56,那么56之前的快速需要用bear替换,如果我对函数的输入是78,则78之前的快速需要用黑色替换

Can someone please help me with this?

有人可以帮我这个吗?

4 个解决方案

#1

I think regular expressions will make this difficult but you should be able to do it using only strpos(), substr() and str_replace().

我认为正则表达式会使这很难,但你应该只能使用strpos(),substr()和str_replace()。

Use strpos to find the location in the string of 56 and 78.

使用strpos查找字符串56和78中的位置。
Then cut the string up into substrings at these points using substr.

然后使用substr将字符串切割成这些点处的子串。
Now, replace 'quick' with the correct variable, depending on whether 56 or 78 was sent to the function and which substring you are dealing with.

现在,将'quick'替换为正确的变量,具体取决于是否将56或78发送到函数以及您正在处理哪个子字符串。

#2

Instead of working with preg_replace, use substr_replace to do your string replacement and strpos to find the start and end points within the string based on the parameters you pass. Your pattern is a simple string, so it doesn't require a regular expression, and substr_replace will allow you to specify a start and end point within the string to do replacements (which seems to be what you're looking for).

不使用preg_replace,而是使用substr_replace进行字符串替换,并使用strpos根据您传递的参数查找字符串中的起点和终点。您的模式是一个简单的字符串,因此它不需要正则表达式,substr_replace将允许您指定字符串中的起点和终点以进行替换(这似乎是您正在寻找的)。

EDIT:

Based on your comment, it sounds like you have to do a lot of checking. I haven't tested this, so it may have a bug or two, but try a function like this:

根据您的评论,听起来您必须进行大量检查。我没有测试过这个,所以它可能有一两个bug,但尝试这样的函数:

function replace($number, $pattern, $replacement)
{
    $input = "The quick sample_text_1 56 quick sample_text_2 78 fox jumped over the lazy dog.";
    $end_pos = strpos($input, $number);
    $output = "";
    if($end_pos !== false && substr_count($input, $pattern, 0, $end_pos))
    {
        $start_pos = strrpos(substr($input, 0, $end_pos), $pattern);
        $output = substr_replace($input, $replacement, $start_pos, ($start_pos + strlen($pattern)));
    }
    return $output;
}

This function does the following:

此功能执行以下操作:

First, check that the "number" parameter even exists in the string ($end_pos !== false)

首先,检查字符串中是否存在“number”参数($ end_pos!== false)

Check that your pattern exists at least once in between teh beginning of the string and the position of the number (substr_count($input, $pattern, 0, $end_pos))

检查您的模式在字符串的开头和数字的位置之间至少存在一次(substr_count($ input,$ pattern,0,$ end_pos))

Use strrpos function to get the position of the last occurrence of the pattern within the substring

使用strrpos函数获取子字符串中最后一次出现的模式的位置

Use the start position and the length of the pattern to insert your replacement string using substr_replace

使用模式的起始位置和长度来使用substr_replace插入替换字符串

#3

Try this:

$searchArray = array("word1", "sound2", "etc3");
$replaceArray = array("word one", "sound two", "etc three");
$intoString = "Here is word1, as well sound2 and etc3";
//now let's replace
print str_replace($searchArray, $replaceArray, $intoString);
//it should print "Here is word one, as well sound two and etc three"

#4

You are doing it the wrong way. Instead depending on your function input you should use the correct find and replace values. Just create a map of find and replace values depending on your function input value. Like:

你这样做是错误的。取决于您的函数输入,您应该使用正确的查找和替换值。只需根据函数输入值创建查找和替换值的映射。喜欢:

$map = array(
  56 => array('patterns' => array(), 'replacements' => array()),
  78 => array(...)
);

#1