How would I replace all space characters with letter "_" except spaces inbetween characters "a" and "b" like this "a b".
如何用字母“_”替换所有空格字符,除了字符“a”和“b”之间的空格,如“a b”。
// this is what I have so far to save someone time (that's a joke)
var result:String = string.replace(/ /g, "_");
Oh this is in JavaScript.
哦,这是在JavaScript中。
2 个解决方案
#1
4
Use this:
var result:String = string.replace(/([^a]) | ([^b])/g, "$1_$2");
A simplified explanation of the above is that it replaces a space that either:
上面的简化说明是它取代了以下任何一个空间:
- is preceded by a character other than
a - is followed by a character other than
b
之前是除了a之外的字符
之后是b以外的字符
Note: to generalize the regex to include tabs and newlines, use \s, like this:
注意:要将正则表达式概括为包含制表符和换行符,请使用\ s,如下所示:
var result:String = string.replace(/([^a])\s|\s([^b])/g, "$1_$2");
#2
2
Try this regex:
试试这个正则表达式:
/(?!a)\s(?!b)/g
Edit: This is not the best solution as KendallFrey pointed out.
编辑:这不是KendallFrey指出的最佳解决方案。
#1
4
Use this:
var result:String = string.replace(/([^a]) | ([^b])/g, "$1_$2");
A simplified explanation of the above is that it replaces a space that either:
上面的简化说明是它取代了以下任何一个空间:
- is preceded by a character other than
a - is followed by a character other than
b
之前是除了a之外的字符
之后是b以外的字符
Note: to generalize the regex to include tabs and newlines, use \s, like this:
注意:要将正则表达式概括为包含制表符和换行符,请使用\ s,如下所示:
var result:String = string.replace(/([^a])\s|\s([^b])/g, "$1_$2");
#2
2
Try this regex:
试试这个正则表达式:
/(?!a)\s(?!b)/g
Edit: This is not the best solution as KendallFrey pointed out.
编辑:这不是KendallFrey指出的最佳解决方案。