使用sed或awk枚举替换

Given the plain text file with lines

给定带有行的纯文本文件

bli foo bla
 abc
 dfg
bli foo bla
 hik
 lmn

what sed or awk magic transforms it to

什么sed或awk魔术将它转化为

bli foo_01 bla
 abc
 dfg
bli foo_02 bla
 hik
 lmn

so that every occurence of 'foo' is replaced by 'foo_[occurence number]'.

这样'foo'的每次出现都被'foo_ [出现次数]'取代。

3 个解决方案

#1

This is another way to express radoulov's answer

这是表达radoulov答案的另一种方式

awk '/foo/ {sub(/foo/, "&_" sprintf("%02d",++c))} 1' infile

You should take care that you don't match "foobar" while looking for "foo":

在寻找“foo”时,你应该注意你不匹配“foobar”:

gawk '/\<foo\>/ {sub(/\<foo\>/, "&_" sprintf("%02d",++c))} 1'

#2

awk '!/foo/||sub(/foo/,"&_"++_)' infile

Use gawk, nawk or /usr/xpg4/bin/awk on Solaris.

在Solaris上使用gawk,nawk或/ usr / xpg4 / bin / awk。

#3

This probably isn't what you require, but it might give some ideas in the right direction.

这可能不是您所需要的,但它可能会给出正确方向的一些想法。

Administrator@snadbox3 ~
$ cd c:/tmp

Administrator@snadbox3 /cygdrive/c/tmp
$ cat <<-eof >foo.txt
> foo
>  abc
>  dfg
> foo
>  hik
>  lmn
> eof

Administrator@snadbox3 /cygdrive/c/tmp
$ awk '/^foo$/{++fooCount; print($0 "_" fooCount);} /^ /{print}' foo.txt
foo_1
 abc
 dfg
foo_2
 hik
 lmn

EDIT:

I'm a day late and a penny short, again ;-(

我又来晚了一分钱又短了一次;-(

EDIT2:

Character encodings is another thing to lookout for... Java source code isn't necessarily in the systems default encoding... it's quit UTF-8 encoded, to allow for any embedded "higher order entities" ;-) Many *nix utilities still aren't charset-aware.

字符编码是值得关注的另一件事... Java源代码不一定是系统默认编码...它退出UTF-8编码,允许任何嵌入的“更高阶实体”;-)许多* nix实用程序仍然没有charset意识。

#1