Python实现栈

时间:2022-04-22 16:25:05

栈的操作


  • Stack() 创建一个新的空栈
  • push(item) 添加一个新的元素item到栈顶
  • pop() 弹出栈顶元素
  • peek() 返回栈顶元素
  • is_empty() 判断栈是否为空
  • size() 返回栈的元素个数

class Stack:
def __init__(self):
self.items = [] def isEmpty(self):
return self.items == [] def push(self, item):
self.items.append(item) def pop(self):
return self.items.pop() def peek(self):
return self.items[len(self.items)-1] def size(self):
return len(self.items)
from pythonds.basic.stack import Stack

s = Stack()

print(s.isEmpty())
s.push(4)
s.push('dog')
print(s.peek())
s.push(True)
print(s.size())
print(s.isEmpty())
s.push(8.4)
print(s.pop())
print(s.pop())
print(s.size())

用栈处理简单括号匹配问题

from pythonds.basic.stack import Stack

def parChecker(symbolString):
s = Stack()
balanced = True
index = 0
while index < len(symbolString) and balanced:
symbol = symbolString[index]
if symbol == "(":
s.push(symbol)
else:
if s.isEmpty():
balanced = False
else:
s.pop() index = index + 1 if balanced and s.isEmpty():
return True
else:
return False print(parChecker('((()))'))
print(parChecker('(()'))

多括号匹配问题

from pythonds.basic.stack import Stack

def parChecker(symbolString):
s = Stack()
balanced = True
index = 0
while index < len(symbolString) and balanced:
symbol = symbolString[index]
if symbol in "([{":
s.push(symbol)
else:
if s.isEmpty():
balanced = False
else:
top = s.pop()
if not matches(top,symbol):
balanced = False
index = index + 1
if balanced and s.isEmpty():
return True
else:
return False def matches(open,close):
opens = "([{"
closers = ")]}"
return opens.index(open) == closers.index(close) print(parChecker('{{([][])}()}'))
print(parChecker('[{()]'))

进制转换

from pythonds.basic.stack import Stack

def baseConverter(decNumber,base):
digits = "0123456789ABCDEF" remstack = Stack() while decNumber > 0:
rem = decNumber % base
remstack.push(rem)
decNumber = decNumber // base newString = ""
while not remstack.isEmpty():
newString = newString + digits[remstack.pop()] return newString print(baseConverter(25,2))
print(baseConverter(25,16))