如何在Linux shell中找到随机文件

How to pick 100 files randomly from a directory by Linux shell. I read other topic, 'shuf' command can do this: find . -type f | shuf -n100, but our environments do not have 'shuf' cmd. Is there other method to do this? use bash, awk, sed or sth else?

如何从Linux shell中随机抽取100个文件。我读过另一个话题，“shuf”命令可以做到:查找。-type f | shuf -n100，但我们的环境没有“shuf”cmd。还有别的方法吗?用bash、awk、sed还是别的什么?

3 个解决方案

#1

This should work on your CentOS5:

这应该适用于你的简历。

shuf() { awk 'BEGIN{srand()}{print rand()"\t"$0}' "$@" | sort | cut -f2- ;}

This comes from a comment by Meow on https://*.com/a/2153889/5844347

这来自Meow对https://*.com/a/2153889/5844347的评论

Use like so: find . -type f | shuf | head -100

像这样使用:find。-type f | shuf | head -100

#2

You can get a directory listing, then randomize it, then pick the top N lines.

你可以得到一个目录列表，然后随机化它，然后选择前N行。

ls | sort -R | head -n 100

Replace ls with an appropriate find command if you want a recursive listing or need finer control of the files to be included.

如果您想要递归清单或需要更好地控制要包含的文件，请使用适当的find命令替换ls。

#3

# To get a integer number between 1 to 100 :
N=`echo|awk 'srand() {print 99*rand() + 1 }' | sed -e "s/\..*$//g"`
echo $N

# To get the Nth file :
find . -type f  | head -${N} | tail -1

# To get 100 files randomly :
for i in $(seq 1 100 )
N=`echo|awk 'srand() {print 99*rand() + 1 }' | sed -e "s/\..*$//g"` 
find . -type f  | head -${N} | tail -1
done

#1