I executed the following command:
我执行了以下命令:
find / -type f -name fs-type -exec svnlook tree {} \; |egrep "/$"
The result was
结果是
svnlook: Can't open file '/var/lib/svn/repos/b1me/products/payone/generic/code/core/db/fs-type/format': Not a directory
svnlook: Can't open file '/var/lib/svn/repos/b1me/products/payone/generic/code/fees/db/fs-type/format': Not a directory
Maybe I should make find command give me the path without db/fs-type/format in other words I should clip the output of find. How can I do this?
也许我应该让find命令给我没有db / fs-type / format的路径换句话说我应该剪切find的输出。我怎样才能做到这一点?
2 个解决方案
#1
0
First you can give
首先你可以给
find ... -not -path "*/db/*"
to find.
#2
0
This is what you're looking for
这就是你要找的东西
find Subversion -type d -name db -exec svnlook tree {}/.. \; | egrep "/$"
Your command was failing because svnlook expects a directory argument not a file one.
您的命令失败,因为svnlook期望目录参数不是文件参数。
#1
0
First you can give
首先你可以给
find ... -not -path "*/db/*"
to find.
#2
0
This is what you're looking for
这就是你要找的东西
find Subversion -type d -name db -exec svnlook tree {}/.. \; | egrep "/$"
Your command was failing because svnlook expects a directory argument not a file one.
您的命令失败,因为svnlook期望目录参数不是文件参数。