I have a log file log .txt which is having the data in below format
我有一个日志文件log .txt,它具有以下格式的数据
Name=abc Date=20140710
Name=xyz Date=20140715
Name=pqr Date=20140810 And so on
I am fetching the data based on today's date and appending it to a log file in new line
我根据今天的日期获取数据并将其附加到新行的日志文件中
today=$(date --date "+1 week" +%Y%m%d)
grep $today log.txt $'\r' >> append_file.txt
But when I am running the script, it is giving me exception like
但是当我运行脚本时,它给了我异常
: No such file or directory
Also, in the append_file.txt, it is keeping the data as
此外,在append_file.txt中,它将数据保持为
log.txt:Name=abc Date=20140710
Ideally it should keep only the data i.e.
理想情况下,它应该只保留数据,即
Name=abc Date=20140710
Actually, my end point objective is mail the content of append_file.txt and I want the data line wise...... like this
实际上,我的终点目标是邮件append_file.txt的内容,我希望数据行明智......就像这样
Name=abc Date=20140710
Name=mno Date=20140710
At present, it is mailing the data in single line Name=abc Date=20140710 Name=mno Date=20140710
目前,它是以单行邮寄数据名称= abc日期= 20140710名称= mno日期= 20140710
Any suggestion ?
有什么建议吗?
1 个解决方案
#1
1
Your output looks like:
您的输出如下:
log.txt:Name=abc Date=20140710
Because grep thinks that you're giving more than one file to work with.
因为grep认为你提供了多个文件。
The problem is $'\r' in this line:
问题是$'\ r'在这一行:
grep $today log.txt $'\r' >> append_file.txt
Replace it by:
替换为:
grep $today log.txt >> append_file.txt
or if you need to insert \r at the end of each line:
或者如果您需要在每行的末尾插入\ r \ n:
grep $today log.txt | sed -e 's/$/\r/g' >> append_file.txt
#1
1
Your output looks like:
您的输出如下:
log.txt:Name=abc Date=20140710
Because grep thinks that you're giving more than one file to work with.
因为grep认为你提供了多个文件。
The problem is $'\r' in this line:
问题是$'\ r'在这一行:
grep $today log.txt $'\r' >> append_file.txt
Replace it by:
替换为:
grep $today log.txt >> append_file.txt
or if you need to insert \r at the end of each line:
或者如果您需要在每行的末尾插入\ r \ n:
grep $today log.txt | sed -e 's/$/\r/g' >> append_file.txt