PROJECT_ROOT = os.path.dirname（__ file__）错误

When i try:
PROJECT_ROOT = os.path.dirname(__file__)
i get error like this:
Traceback (most recent call last):
File "< stdin>", line 1, in <module>
NameError: name '__file__' is not defined

当我尝试:PROJECT_ROOT = os.path.dirname(__ file__)时,我得到如下错误:Traceback(最近一次调用最后一次):文件“ ”,第1行,在 NameError:name'__ file__'不是定义

Does someone know how to fix this?

有人知道如何解决这个问题吗?

3 个解决方案

#1

Run that line of code via an actual module instead of in the Python REPL.

通过实际模块而不是Python REPL运行该行代码。

#2

If you are trying to use __file__ from your interpreter, no __file__ is defined. This is the intended behavior. __file__ is an attribute of modules. Here is a discussion about the subject.

如果您尝试使用解释器中的__file__,则不会定义__file__。这是预期的行为。 __file__是模块的属性。这是关于这个主题的讨论。

You can test by doing this:

你可以这样测试:

~$ echo "print __file__" > test.py
~$ python test.py
test.py

__file__ works in from within modules.

__file__在模块内工作。

Now from the interpreter:

现在来自翻译:

~$ python
Python 2.7.0+ (r27:82500, Sep 15 2010, 18:04:55) 
[GCC 4.4.5] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> print __file__
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
NameError: name '__file__' is not defined

__file__ is not defined

__file__未定义

>>> import test
test.pyc
>>> print __file__
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
NameError: name '__file__' is not defined

__file__ is not defined

__file__未定义

>>> print test.__file__
test.pyc
>>> 

__file__ is defined for the test module

__file__是为测试模块定义的

#3

Please try this in your settings.py :

请在您的settings.py中尝试此操作:

    PROJECT_ROOT = os.path.abspath(os.path.dirname(__file__))