从swift容器下载时文件已损坏

I want to get a file from a swift container in node.

我想从节点中的swift容器中获取文件。

I'm using this code for making a request (largely inspired by this code):

我正在使用此代码发出请求（主要受此代码启发）：

 var client = https.request(options, function(res) {
    var buffers = [];
    res.body='';

    res.on('data', function(buffer) {
       buffers.push(buffer);

    });

    res.on('end', function(err){
      res.body = buffers.join('');
      callback && callback(res);

    });

  });

If download a text file, there's no problem, but for binary data, differences appears between the downloaded file and the original, after some bytes (258 with an mp3 file).

如果下载文本文件，没有问题，但对于二进制数据，在一些字节（带有mp3文件的258）之后，下载的文件和原始文件之间会出现差异。

Have you an idea of what could cause a such corruption? character encoding, ending characters which I have to remove,wrong way to merge the datas,...

你知道什么可能导致这样的腐败吗？字符编码，我必须删除的结束字符，合并数据的错误方法，...

update

更新

I made it work like that:

我让它像那样工作：

  var client = https.request(options, function(res) {
    res.body='';

    res.on('data', function(buffer) {
      res.body+= buffer.toString('binary');
    });

    res.on('end', function(err){
      callback && callback(res);
    });

  });

but it's written in the doc that toString('binary') will be deprecated soon, so it's not the best solution.

但是在文档中写道，toString（'binary'）很快就会被弃用，所以它不是最好的解决方案。

1 个解决方案

#1

  buffers.join('');

Does a string join on the array, which is not what you want for binary data. The correct way to concatenate buffers is

字符串是否在数组上连接，这不是您想要的二进制数据。连接缓冲区的正确方法是

  Buffer.concat(buffers);

See http://nodejs.org/api/buffer.html#buffer_class_method_buffer_concat_list_totallength

见http://nodejs.org/api/buffer.html#buffer_class_method_buffer_concat_list_totallength

So you could do this

所以你可以做到这一点

var client = https.request(options, function(res) {
    var buffers=[];

    res.on('data', function(buffer) {
      buffers.push(buffer);
    });

    res.on('end', function(err){
      res.body=Buffer.concat(Buffers);
      callback && callback(res);
    });
});

But your callback would have to be expecting a Buffer rather than a String. Of course, being binary data, it shouldn't be a String anyway.

但是你的回调必须要求一个Buffer而不是一个String。当然，作为二进制数据，它无论如何都不应该是String。

#1

  buffers.join('');