从url下载json文件时的连接超时

I am trying to download JSON file from this URL: http://map01.eniro.no/search/search.json?index=yp&profile=pl&q=ma%C5%82opolskie&sortOrder=default&pageSize=5 in Java, but I always getting an exception:

我正在尝试从这个URL下载JSON文件:http://map01.eniro.no/search/search.json?在Java中，index=yp&p =pl&q=ma%C5%82opolskie&sortOrder= 5，但我总是有例外:

HTTP Status 500 - Server returned HTTP response code: 405 for URL: http://map01.eniro.no/search/search.json
type Exception report
message Server returned HTTP response code: 405 for URL: http://map01.eniro.no/search/search.json
description The server encountered an internal error that prevented it from fulfilling this request.
exception
java.io.IOException: Server returned HTTP response code: 405 for URL: http://map01.eniro.no/search/search.json
    sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
    sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source)
    sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source)
    java.lang.reflect.Constructor.newInstance(Unknown Source)
    sun.net.www.protocol.http.HttpURLConnection$10.run(Unknown Source)
    sun.net.www.protocol.http.HttpURLConnection$10.run(Unknown Source)
    java.security.AccessController.doPrivileged(Native Method)
    sun.net.www.protocol.http.HttpURLConnection.getChainedException(Unknown Source)
    sun.net.www.protocol.http.HttpURLConnection.getInputStream0(Unknown Source)
    sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)
    MainServlet.callURL(MainServlet.java:108)
    MainServlet.doGet(MainServlet.java:71)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:622)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
    org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
root cause
java.io.IOException: Server returned HTTP response code: 405 for URL: http://map01.eniro.no/search/search.json
    sun.net.www.protocol.http.HttpURLConnection.getInputStream0(Unknown Source)
    sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)
    java.net.HttpURLConnection.getResponseCode(Unknown Source)
    MainServlet.callURL(MainServlet.java:102)
    MainServlet.doGet(MainServlet.java:71)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:622)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
    org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)

This is my function for this task. I tried a lot of different ways to solve this problem but I always get the same. I dont have much experience with HTTP connection programming so I need help.

这是我的功能。我尝试了很多不同的方法来解决这个问题，但是我总是得到同样的结果。我没有太多HTTP连接编程的经验，所以我需要帮助。

public static void callURL() throws IOException {

    URL obj = new URL("http://map01.eniro.no/search/search.json");
    HttpURLConnection con = (HttpURLConnection) obj.openConnection();

    con.setRequestMethod("POST");
    con.setRequestProperty("User-Agent", "Mozilla/5.0 (Windows NT 6.3; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/43.0.2357.124 Safari/537.36");
    con.setRequestProperty("Accept-Language", "pl-PL;q=0.8");

    String urlParameters = "?index=yp&profile=pl&q=małopolskie&sortOrder=default&pageSize=5";

    // Send post request
    con.setDoOutput(true);
    DataOutputStream wr = new DataOutputStream(con.getOutputStream());
    wr.writeBytes(urlParameters);
    wr.flush();
    wr.close();

    int responseCode = con.getResponseCode();
    System.out.println("\nSending 'POST' request to URL : " + myURL);
    System.out.println("Post parameters : " + urlParameters);
    System.out.println("Response Code : " + responseCode);

    BufferedReader in = new BufferedReader(
            new InputStreamReader(con.getInputStream()));
    String inputLine;
    StringBuffer response = new StringBuffer();

    while ((inputLine = in.readLine()) != null) {
        response.append(inputLine);
    }
    in.close();

    System.out.println(response.toString());
}

UPDATE:

更新:

I check my http request by Fiddler app and I have an error in it:

我通过Fiddler app检查我的http请求，我有一个错误:

' Incorrectly formed Request-Line. abs_path was empty (e.g. missing /). RFC2616 '

的错误请求行形成的。abs_path是空的(例如:missing /)。RFC2616”

What does it mean? I thought that request is correct, because in browser I can read this json.

这是什么意思?我认为这个请求是正确的，因为在浏览器中我可以读取这个json。

2 个解决方案

#1

405 is Method Not Allowed. The fact that you have parameters on a querystring suggests you should be doing a GET not a POST

405是不允许使用的方法。查询字符串上有参数这一事实表明，您应该执行GET而不是POST操作

I would try changing con.setRequestMethod("POST"); to con.setRequestMethod("GET");.

我尝试改变con.setRequestMethod(“POST”);con.setRequestMethod("得到");。

#2

as you wanted to get something from server you should make GET request instead of POST.

当你想从服务器上获取一些东西时，你应该发出get请求而不是POST。

Try this,

试试这个,

private static JSONObject getResult() throws JSONException {

        String uri = "http://map01.eniro.no/search/search.json?index=yp&profile=pl&q=ma%C5%82opolskie&sortOrder=default&pageSize=5";

        JSONObject jsonResponse = null;
        try {
            URL url = new URL(uri);
            HttpURLConnection conn = (HttpURLConnection) url.openConnection();
            conn.setDoOutput(true);
            conn.setRequestMethod("GET");
            conn.setRequestProperty("Content-Type", "application/json");

            if (conn.getResponseCode() != 200) {
                throw new RuntimeException("Failed : HTTP error code : "
                        + conn.getResponseCode());
            }

            BufferedReader br = new BufferedReader(new InputStreamReader(
                    (conn.getInputStream())));

            String jsonResponseString = br.readLine();

            jsonResponse = new JSONObject(jsonResponseString);

            conn.disconnect();

        } catch (MalformedURLException e) {

        } catch (IOException e) {

        } catch (JSONException ex) {

        }
        System.out.println("res: " + jsonResponse);
        return jsonResponse;
    }

#1