%% Machine Learning Online Class - Exercise 3 | Part 1: One-vs-all % Instructions
% ------------
%
% This file contains code that helps you get started on the
% linear exercise. You will need to complete the following functions
% in this exericse:
%
% lrCostFunction.m (logistic regression cost function)
% oneVsAll.m
% predictOneVsAll.m
% predict.m
%
% For this exercise, you will not need to change any code in this file,
% or any other files other than those mentioned above.
% %% Initialization
clear ; close all; clc %% Setup the parameters you will use for this part of the exercise
input_layer_size = 400; % 20x20 Input Images of Digits
num_labels = 10; % 10 labels, from 1 to 10
% (note that we have mapped "0" to label 10) %% =========== Part 1: Loading and Visualizing Data =============
% We start the exercise by first loading and visualizing the dataset.
% You will be working with a dataset that contains handwritten digits.
% % Load Training Data
fprintf('Loading and Visualizing Data ...\n') load('ex3data1.mat'); % training data stored in arrays X, y
m = size(X, 1);
size(X, ); X=* size(X, ) = 取行 size(X,) = 取列
解释
% Randomly select 100 data points to display
rand_indices = randperm(m);
sel = X(rand_indices(1:100), :); displayData(sel); fprintf('Program paused. Press enter to continue.\n');
pause; %% ============ Part 2: Vectorize Logistic Regression ============
% In this part of the exercise, you will reuse your logistic regression
% code from the last exercise. You task here is to make sure that your
% regularized logistic regression implementation is vectorized. After
% that, you will implement one-vs-all classification for the handwritten
% digit dataset.
% fprintf('\nTraining One-vs-All Logistic Regression...\n') lambda = 0.1;
[all_theta] = oneVsAll(X, y, num_labels, lambda); fprintf('Program paused. Press enter to continue.\n');
pause; %% ================ Part 3: Predict for One-Vs-All ================
% After ...
pred = predictOneVsAll(all_theta, X); fprintf('\nTraining Set Accuracy: %f\n', mean(double(pred == y)) * 100);