从稀疏数据创建PNG图像

I would like to store a PNG image in Python where the RGB values are given by the list

我想在Python中存储一个PNG图像，其中列表给出RGB值

entries = [
    [1, 2, [255, 255, 0]],
    [1, 5, [255, 100, 0]],
    [2, 5, [0, 255, 110]],
    # ...
    ]

(row, column, RGB triple), together with a default value of [255, 255, 255] and the information about the total dimensions of the image.

(行、列、RGB三元组)，以及默认值[255、255、255]和关于图像总维数的信息。

Using PIL, I could of course translate entries into a dense m-by-n-by-3 matrix, but that doesn't fit into memory; the matrix dimensions can be in the ten thousands.

使用PIL，我当然可以将条目转换成密集的m×n×3矩阵，但这不适合存储;矩阵的维数可以是一万。

Is there another way to create a PNG image with the above information?

是否有其他方法用上述信息创建PNG图像?

2 个解决方案

#1

The PurePNG library writes a file line-by-line and only requires a row iterator:

PurePNG库逐行写一个文件，只需要行迭代器:

def write_png(A, filename):
    m, n = A.shape

    w = png.Writer(n, m, greyscale=True, bitdepth=1)

    class RowIterator:
        def __init__(self, A):
            self.A = A.tocsr()
            self.current = 0
            return

        def __iter__(self):
            return self

        def __next__(self):
            if self.current+1 > A.shape[0]:
                raise StopIteration
            out = numpy.ones(A.shape[1], dtype=bool)
            out[self.A[self.current].indices] = False
            self.current += 1
            return out

    with open(filename, 'wb') as f:
        w.write(f, RowIterator(A))

    return

#2

You could do it like this:

你可以这样做:

from PIL import Image

sparse = [
    [1, 2, [255, 255, 0]],
    [1, 5, [255, 100, 0]],
    [2, 5, [0, 255, 110]],
    ]

im = Image.new("RGB", (20, 20), (255, 255, 255))
for item in sparse:
    x, y, color = item
    im.putpixel((x, y), tuple(color))

im.save("schlomer.png")
im.show()

#1