given an example log file like:
给出一个示例日志文件，如:
interesting stuff
App: 123 blob
some text
other text
ERROR could not find file XYZ
other really cool stuff
App: 123 blob
some text
other text
ERROR stdout blocked
I want to grep the line with 'ERROR' and 'App:' plus the line before 'App:'. With multiple search-patterns and -B 1 i get the matching lines plus the respective line before:
我想用‘ERROR’和‘App:’加上‘App:’之前的那行。通过多种搜索模式和- b1，我得到了匹配行加上之前的相应行:
grep -B 1 -e '^App:.*' -e '.*ERROR.*'
interesting stuff
App: 123 blob
--
other text
ERROR could not find file XYZ
other really cool stuff
App: 123 blob
--
other text
ERROR stdout blocked
(i also don't know where the '--' are coming from) but my desired output is:
(我也不知道“—”从何而来)但我想要的输出是:
interesting stuff
App: 123 blob
ERROR could not find file XYZ
other really cool stuff
App: 123 blob
ERROR stdout blocked
Thank you very much.
非常感谢。
1 个解决方案
#1
3
grep's -B 1 option would apply to all expressions. You can use awk in this case:
grep的- b1选项将适用于所有表达式。在这种情况下，你可以使用awk:
$ awk '/App/ {print line;print} {line=$0} /ERROR/' file
interesting stuff
App: 123 blob
ERROR could not find file XYZ
other really cool stuff
App: 123 blob
ERROR stdout blocked
$
#1
3
grep's -B 1 option would apply to all expressions. You can use awk in this case:
grep的- b1选项将适用于所有表达式。在这种情况下，你可以使用awk:
$ awk '/App/ {print line;print} {line=$0} /ERROR/' file
interesting stuff
App: 123 blob
ERROR could not find file XYZ
other really cool stuff
App: 123 blob
ERROR stdout blocked
$