I have some object.ID-s which I try to store in the user session as tuple. When I add first one it works but tuple looks like (u'2',) but when I try to add new one using mytuple = mytuple + new.id got error can only concatenate tuple (not "unicode") to tuple.
我有一些对象。ID-s，我将它作为元组存储在用户会话中。当我添加第一个时，它可以工作，但是tuple看起来像(u'2')，但是当我尝试使用mytuple = mytuple + new添加新一个时。id有错误只能将tuple(不是“unicode”)连接到tuple。
6 个解决方案
#1
181
You need to make the second element a 1-tuple, eg:
你需要把第二个元素做成一个1-tuple，例如:
a = ('2',)
b = 'z'
new = a + (b,)
#2
22
From tuple to list to tuple :
从元组到列表到元组:
a = ('2',)
b = 'b'
l = list(a)
l.append(b)
tuple(l)
Or with a longer list of items to append
或者附加一个较长的项目列表
a = ('2',)
items = ['o', 'k', 'd', 'o']
l = list(a)
for x in items:
l.append(x)
print tuple(l)
gives you
给你
>>>
('2', 'o', 'k', 'd', 'o')
The point here is: List is a mutable sequence type. So you can change a given list by adding or removing elements. Tuple is an immutable sequence type. You can't change a tuple. So you have to create a new one.
这里的要点是:List是一个可变的序列类型。因此，您可以通过添加或删除元素来更改给定的列表。Tuple是不可变的序列类型。你不能改变一个元组。所以你必须创建一个新的。
#3
18
Since Python 3.5 (PEP 448) you can do unpacking within a tuple, list set, and dict:
由于Python 3.5 (PEP 448)，您可以在tuple、list set和dict类型中进行拆包:
a = ('2',)
b = 'z'
new = (*a, b)
#4
10
>>> x = (u'2',)
>>> x += u"random string"
Traceback (most recent call last):
File "<pyshell#11>", line 1, in <module>
x += u"random string"
TypeError: can only concatenate tuple (not "unicode") to tuple
>>> x += (u"random string", ) # concatenate a one-tuple instead
>>> x
(u'2', u'random string')
#5
9
Tuple can only allow adding tuple to it. The best way to do it is:
Tuple只能允许向它添加Tuple。最好的办法是:
mytuple =(u'2',)
mytuple +=(new.id,)
I tried the same scenario with the below data it all seems to be working fine.
我用下面的数据尝试了同样的场景，一切似乎都很好。
>>> mytuple = (u'2',)
>>> mytuple += ('example text',)
>>> print mytuple
(u'2','example text')
#6
-1
#1 form
a = ('x', 'y')
b = a + ('z',)
print(b)
#2 form
a = ('x', 'y')
b = a + tuple('b')
print(b)
#1
181
You need to make the second element a 1-tuple, eg:
你需要把第二个元素做成一个1-tuple，例如:
a = ('2',)
b = 'z'
new = a + (b,)
#2
22
From tuple to list to tuple :
从元组到列表到元组:
a = ('2',)
b = 'b'
l = list(a)
l.append(b)
tuple(l)
Or with a longer list of items to append
或者附加一个较长的项目列表
a = ('2',)
items = ['o', 'k', 'd', 'o']
l = list(a)
for x in items:
l.append(x)
print tuple(l)
gives you
给你
>>>
('2', 'o', 'k', 'd', 'o')
The point here is: List is a mutable sequence type. So you can change a given list by adding or removing elements. Tuple is an immutable sequence type. You can't change a tuple. So you have to create a new one.
这里的要点是:List是一个可变的序列类型。因此，您可以通过添加或删除元素来更改给定的列表。Tuple是不可变的序列类型。你不能改变一个元组。所以你必须创建一个新的。
#3
18
Since Python 3.5 (PEP 448) you can do unpacking within a tuple, list set, and dict:
由于Python 3.5 (PEP 448)，您可以在tuple、list set和dict类型中进行拆包:
a = ('2',)
b = 'z'
new = (*a, b)
#4
10
>>> x = (u'2',)
>>> x += u"random string"
Traceback (most recent call last):
File "<pyshell#11>", line 1, in <module>
x += u"random string"
TypeError: can only concatenate tuple (not "unicode") to tuple
>>> x += (u"random string", ) # concatenate a one-tuple instead
>>> x
(u'2', u'random string')
#5
9
Tuple can only allow adding tuple to it. The best way to do it is:
Tuple只能允许向它添加Tuple。最好的办法是:
mytuple =(u'2',)
mytuple +=(new.id,)
I tried the same scenario with the below data it all seems to be working fine.
我用下面的数据尝试了同样的场景，一切似乎都很好。
>>> mytuple = (u'2',)
>>> mytuple += ('example text',)
>>> print mytuple
(u'2','example text')
#6
-1
#1 form
a = ('x', 'y')
b = a + ('z',)
print(b)
#2 form
a = ('x', 'y')
b = a + tuple('b')
print(b)