使用正则表达式删除括号中的所有内容

I've used the following regex to try to remove parentheses and everything within them in a string called name.

我已经使用以下正则表达式尝试在名为name的字符串中删除括号及其中的所有内容。

name.replaceAll("\\(.*\\)", "");

For some reason, this is leaving name unchanged. What am I doing wrong?

由于某种原因，这是保持名称不变。我究竟做错了什么？

5 个解决方案

#1

Strings are immutable. You have to do this:

字符串是不可变的。你必须这样做：

name = name.replaceAll("\\(.*\\)", "");

Edit: Also, since the .* is greedy, it will kill as much as it can. So "(abc)(def)" will be turned into "".

编辑：此外，由于。*是贪婪的，它会尽可能多地杀死它。所以“（abc）（def）”将变成“”。

#2

As mentionend by by Jelvis, ".*" selects everything and converts "(ab) ok (cd)" to ""

正如Jelvis所提到的，“。*”选择所有内容并将“（ab）ok（cd）”转换为“”

The version below works in these cases "(ab) ok (cd)" -> "ok", by selecting everything except the closing parenthesis and removing the whitespaces.

下面的版本适用于这些情况“（ab）ok（cd）” - >“ok”，通过选择除右括号以外的所有内容并删除空格。

test = test.replaceAll("\\s*\\([^\\)]*\\)\\s*", " ");

#3

String.replaceAll() doesn't edit the original string, but returns the new one. So you need to do:

String.replaceAll（）不会编辑原始字符串，但会返回新字符串。所以你需要这样做：

name = name.replaceAll("\\(.*\\)", "");

#4

If you read the Javadoc for String.replaceAll(), you'll notice that it specifies that the resulting string is the return value.

如果您读取String.replaceAll（）的Javadoc，您会注意到它指定结果字符串是返回值。

More generally, Strings are immutable in Java; they never change value.

更一般地说，字符串在Java中是不可变的;他们永远不会改变价值

#5

I'm using this function:

我正在使用这个功能：

public static String remove_parenthesis(String input_string, String parenthesis_symbol){
    // removing parenthesis and everything inside them, works for (),[] and {}
    if(parenthesis_symbol.contains("[]")){
        return input_string.replaceAll("\\s*\\[[^\\]]*\\]\\s*", " ");
    }else if(parenthesis_symbol.contains("{}")){
        return input_string.replaceAll("\\s*\\{[^\\}]*\\}\\s*", " ");
    }else{
        return input_string.replaceAll("\\s*\\([^\\)]*\\)\\s*", " ");
    }
}

You can call it like this:

你可以这样称呼它：

remove_parenthesis(g, "[]");
remove_parenthesis(g, "{}");
remove_parenthesis(g, "()");

#1