解决序列化中的问题java.io.StreamCorruptedException: invalid stream header:EFBFBDEF

Java代码  

1. public class TestDeserialize extends TestCase {  
2.     public void testDeserialize() throws IOException, ClassNotFoundException {  
3.         ByteArrayOutputStream baos = new ByteArrayOutputStream();  
4.         ObjectOutputStream oos = new ObjectOutputStream(baos);  
5.         BigInteger bi = new BigInteger("0");  
6.         oos.writeObject(bi);  
7.         String str = baos.toString();  
8.         System.out.println(str);  
9.         ObjectInputStream ois = new ObjectInputStream(new BufferedInputStream(new ByteArrayInputStream(str.getBytes())));  
10.         Object obj = ois.readObject();  
11.     }  
12. }  

 

抛出错误

 

 

Java代码  

1. [junit] ------------- ---------------- ---------------  
2.    [junit] Testcase: testDeserialize(org.jboss.remoting.loading.TestDeserialize):   Caused an ERROR  
3.    [junit] invalid stream header: EFBFBDEF  
4.    [junit] java.io.StreamCorruptedException: invalid stream header: EFBFBDEF  
5.    [junit]  at java.io.ObjectInputStream.readStreamHeader(ObjectInputStream.java:783)  
6.    [junit]  at java.io.ObjectInputStream.<init>(ObjectInputStream.java:280)  
7.    [junit]  at org.jboss.remoting.loading.TestDeserialize.testDeserialize(TestDeserialize.java:20)  
8.    [junit]   
9.    [junit]   
10.    [junit] Test org.jboss.remoting.loading.TestDeserialize FAILED  

 

修改成为

 

 

Java代码  

1. public void testDeserialize() throws IOException, ClassNotFoundException {  
2.     ByteArrayOutputStream baos = new ByteArrayOutputStream();  
3.     ObjectOutputStream oos = new ObjectOutputStream(baos);  
4.     BigInteger bi = new BigInteger("0");  
5.     oos.writeObject(bi);  
6.     byte[] str = baos.toByteArray();  
7.     ObjectInputStream ois = new ObjectInputStream(new BufferedInputStream(new ByteArrayInputStream(str)));  
8.     Object obj = ois.readObject();  
9.     assertNotNull(obj);  
10.     assertEquals(obj.getClass().getName(),"java.math.BigInteger");  
11.     assertEquals(((BigInteger)obj).intValue(), 0);  
12. }  

 

搞定，原因请见

 

http://bugs.sun.com/bugdatabase/view_bug.do?bug_id=4968673

 

 

The provided test code serializes an object to a ByteArrayOutputStream,
converts the generated byte array into a string using the
ByteArrayOutputStream.toString() method, converts the string back into a byte
array using the String.getBytes() method, and then attempts to deserialize the
object from the byte array using a ByteArrayInputStream.  This procedure will
in most cases fail because of the transformations that take place within
ByteArrayOutputStream.toString() and String.getBytes(): in order to convert the
contained sequence of bytes into a string, ByteArrayOutputStream.toString()
decodes the bytes according to the default charset in effect; similarly, in
order to convert the string back into a sequence of bytes, String.getBytes()
encodes the characters according to the default charset.

Converting bytes into characters and back again according to a given charset is
generally not an identity-preserving operation.  As the javadoc for the
String(byte[], int, int) constructor (which is called by
ByteArrayOutputStream.toString()) states, "the behavior ... when the given
bytes are not valid in the default charset is unspecified".  In the test case
provided, the first two bytes of the serialization stream, 0xac and 0xed (see
java.io.ObjectStreamConstants.STREAM_MAGIC), both get mapped to the character
'?' since they are not valid in the default charset (ISO646-US in the JDK I'm
running).  The two '?' characters are then mapped back to the byte sequence
0x3f 0x3f in the reconstructed data stream, which do not constitute a valid
header. 

The solution, from the perspective of the test case, is to use
ByteArrayOutputStream.toByteArray() instead of toString(), which will yield the
raw byte sequence; this can then be fed directly to the
ByteArrayInputStream(byte[]) constructor.

注：在转换成字符串的时候如果使用Base64则可以避免该问题